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jarptica [38.1K]
3 years ago
10

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the sub

stance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.
Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

True

Explanation:

The main differences between a physical property and a chemical property are mentioned below:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.

While A chemical property describes the ability of a substance to undergo a specific chemical change.

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Which term best describes the basic unit that makes up all matter?
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Answer:

C. Atoms

Explanation:

The basic unit of matter and the smallest, indivisible unit of a chemical element. It comprises a nucleus (neutrons + protons) that is surrounded by a cloud of electrons.

6 0
2 years ago
10. Inertia causes your books on the car seat to continue moving forward even after you brake. TrueFalse 11. Tires with little o
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10. True

11. True

12. True

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14. False

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3 years ago
Consider this situation: A rope is used to lift an actor upward off the stage. Of the forces listed, identify which act upon the
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3 years ago
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How many times is larger than a centigram is a dekagram
S_A_V [24]
A decagram is 1000 times bigger than a centigram
8 0
3 years ago
We would like to place an object 45.0cm in front of a lens and have its image appear on a screen 90.0cm behind the lens. What mu
liubo4ka [24]

Answer:

the radii of curvature is 30 cm.

Explanation:

given,

object is place at = 45 cm

image appears at = 90 cm

focal length = ?

refractive index = 1.5

radii of curvature = ?

\dfrac{1}{f} = \dfrac{1}{u} +\dfrac{1}{v}

\dfrac{1}{f} = \dfrac{1}{45} +\dfrac{1}{90}

f = 30 cm

using lens formula

\dfrac{1}{f} = (n-1)(\dfrac{1}{R_1} -\dfrac{1}{R_2})

R_1 = R\ and\ R_2 = -R

\dfrac{1}{f} = (n-1)(\dfrac{1}{R} +\dfrac{1}{R})

R = (n -1)\ f

R = 2(1.5 -1)\ 30

R = 30 cm

hence, the radii of curvature is 30 cm.

3 0
3 years ago
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