Answer:
c = 4,444.44
Explanation:
You have the following expression for the acceleration of the projectile:
(1)
s: distance to the ground of the projectile
To find the value of the constant c you use the following formula:
(2)
vo: initial velocity = 0 m/s
v: final speed = 200 m/s
Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m
You replace the expression (1) into the expression (2):

You do the constant c in the last equation, then you replace the values of v, s and Δs:

TTAAGGCCTAGC
hope this helps
Answer:
t = 2.13 s
Explanation:
given,
height of the building = 22.3 m
horizontal distance = 127 m
acceleration due to gravity = 9.8 m/s²
time for which ball is in motion = ?
using equation of motion

initial velocity is zero



t = √4.551
t = 2.13 s