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jarptica [38.1K]
3 years ago
10

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the sub

stance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.
Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

True

Explanation:

The main differences between a physical property and a chemical property are mentioned below:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.

While A chemical property describes the ability of a substance to undergo a specific chemical change.

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A rocket, blasting into space, accelerates at 2 m/s^2 for 20 seconds. What is its speed at the end of 20 seconds?​
OLEGan [10]

Answer:

  Acceleration  =  (change in speed)  /  (time for the change)

Change in speed = (ending speed) - (beginning speed)

                           =     (3,600 mi/hr) - ( 0 )

                           =       3,600 mi/hr

                           =     same as  1 mile/second.

Acceleration  =  (1 mi/sec) / (10 sec)

                     =     0.1 mi/sec² .

But 1 mile = 5,280 ft,

so

                      0.1 mi/s²  =  528 ft/s²          

Explanation:

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4 0
3 years ago
Do you think it would take more force to transport five blocks in the sled or in the wagon?
enot [183]
It will depend on the frictional force involved in the two. I think it will take more force in sled.
6 0
3 years ago
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In an experiment designed to measure the strength of a uniform magnetic field produced by a set of coils, electrons are accelera
Arlecino [84]

Answer:

the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

Explanation:

Given;

potential difference, V =  278 V

radius of the circular path, r = 6.46 cm = 0.0646 m

charge of electron, q = 1.60218 × 10⁻¹⁹ C

mass of electron, m = 9.10939 × 10⁻³¹ kg

The magnitude of the magnetic field is given as;

B = \frac{M_e*v}{q*r}

where;

B is the magnitude of the magnetic field

M_e is mass of the electron

v is velocity of the electron

r is the radius of the circular path

q is charge of the electron

Determine velocity of the electron from kinetic energy equation;

K = \frac{1}{2} M_ev^2\\\\Vq = \frac{1}{2} M_ev^2\\\\v^2 = \frac{2qV}{M_e} \\\\v = \sqrt{\frac{2qV}{M_e}} = \sqrt{\frac{2*1.602*10^{-19}*278}{9.109*10^{-31}}} = 9.8886*10^{6} \ m/s

the magnitude of the magnetic field:

B = \frac{M_e*v}{q*r} \\\\B = \frac{(9.109*10^{-31})*(9.8886*10^6)}{(1.602*10^{-19})*(0.0646)} = 8.704*10^{-4} \ T

Therefore, the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

5 0
3 years ago
PLS HURRY THIS IS DUE TODAY!!!
loris [4]

Answer:

B. between carbon and oxygen

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8 0
2 years ago
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Science
Elena-2011 [213]

sorry accidentally posted here.

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