Which of the following would increase the dissolution rate of most solids in a liquid?

1 answer:

8 0

Unfortunately, you have not included in here the choices in which we could choose the best answer from. However, some of the reasons for the increase in the dissolution rate of most solid in liquid is the increase in temperature of the solution (liquid) and also the decrease in sizes of the solids which will consequently increase the surface area.

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Which molecule would be harder to break apart, O2 with double bonds or

Sliva [168]

Answer:

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Explanation:

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3 years ago

When of a certain molecular compound X are dissolved in of benzene , the freezing point of the solution is measured to be . Calc

puteri [66]

The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between freezing point depression and molality. With this last one, is possible to calculate molar mass or molar weight of a compound.

Freezing Point Depression occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

Molality or molal concentration is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

$m=\frac{moles(solute)}{kg(solvent)}$