Amount of work done is zero and so power = 0 watts.
<u>Explanation:</u>
Power is the rate at which work is done, or W divided by delta t. Since the barbell is not moving, the weightlifter is not doing work on the barbell.Therefore, if the work done is zero, then the power is also zero.It may seem unusual that the data given in question is versatile i.e. A weightlifter exerts an upward force on a 1000-N barbell and holds it at a height of 1 meter for 2 seconds. But, still the answer is zero watts , this was a tricky question although conceptual basis of question was good! Power is dependent on amount of work done which is further related to displacement and here the net displacement is zero ! Hence, amount of work done is zero and so power = 0 watts.
Answer:
Part a)
%
Part b)
%
Explanation:
As we know that total power used in the room is given as
![P = P_1 + P_2 + P_3 + P_4](https://tex.z-dn.net/?f=P%20%3D%20P_1%20%2B%20P_2%20%2B%20P_3%20%2B%20P_4)
here we have
![P_1 = (110)(3) = 330 W](https://tex.z-dn.net/?f=P_1%20%3D%20%28110%29%283%29%20%3D%20330%20W)
![P_2 = 100 W](https://tex.z-dn.net/?f=P_2%20%3D%20100%20W)
![P_3 = 60 W](https://tex.z-dn.net/?f=P_3%20%3D%2060%20W)
![P_4 = 3 W](https://tex.z-dn.net/?f=P_4%20%3D%203%20W)
![P = 330 + 100 + 60 + 3](https://tex.z-dn.net/?f=P%20%3D%20330%20%2B%20100%20%2B%2060%20%2B%203)
![P = 493 W](https://tex.z-dn.net/?f=P%20%3D%20493%20W)
Part a)
Since power supply is at 110 Volt so the current obtained from this supply is given as
![110\times i = 493](https://tex.z-dn.net/?f=110%5Ctimes%20i%20%3D%20493%20)
![i = 4.48 A](https://tex.z-dn.net/?f=i%20%3D%204.48%20A)
now resistance of transmission line
![R = \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
![R = \frac{(2.8 \times 10^{-8})(10\times 10^3)}{\pi(4.126\times 10^{-3})^2}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B%282.8%20%5Ctimes%2010%5E%7B-8%7D%29%2810%5Ctimes%2010%5E3%29%7D%7B%5Cpi%284.126%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D)
![R = 5.23 \ohm](https://tex.z-dn.net/?f=R%20%3D%205.23%20%5Cohm)
now power loss in line is given as
![P = i^2 R](https://tex.z-dn.net/?f=P%20%3D%20i%5E2%20R)
![P = (4.48)^2(5.23)](https://tex.z-dn.net/?f=P%20%3D%20%284.48%29%5E2%285.23%29)
![P = 105 W](https://tex.z-dn.net/?f=P%20%3D%20105%20W)
Now percentage loss is given as
![percentage = \frac{loss}{supply} \times 100](https://tex.z-dn.net/?f=percentage%20%3D%20%5Cfrac%7Bloss%7D%7Bsupply%7D%20%5Ctimes%20100)
![percentage = \frac{105}{493} \times 100](https://tex.z-dn.net/?f=percentage%20%3D%20%5Cfrac%7B105%7D%7B493%7D%20%5Ctimes%20100)
%
Part b)
now same power must have been supplied from the supply station at 110 kV, so we have
![110 \times 10^3 (i ) = 493](https://tex.z-dn.net/?f=110%20%5Ctimes%2010%5E3%20%28i%20%29%20%3D%20493)
![i = 4.48\times 10^{-3} A](https://tex.z-dn.net/?f=i%20%3D%204.48%5Ctimes%2010%5E%7B-3%7D%20A)
now power loss in line is given as
![P = i^2 R](https://tex.z-dn.net/?f=P%20%3D%20i%5E2%20R)
![P = (4.48 \times 10^{-3})^2(5.23)](https://tex.z-dn.net/?f=P%20%3D%20%284.48%20%5Ctimes%2010%5E%7B-3%7D%29%5E2%285.23%29)
![P = 1.05 \times 10^{-4} W](https://tex.z-dn.net/?f=P%20%3D%201.05%20%5Ctimes%2010%5E%7B-4%7D%20W)
Now percentage loss is given as
![percentage = \frac{loss}{supply} \times 100](https://tex.z-dn.net/?f=percentage%20%3D%20%5Cfrac%7Bloss%7D%7Bsupply%7D%20%5Ctimes%20100)
![percentage = \frac{1.05 \times 10^{-4}}{493} \times 100](https://tex.z-dn.net/?f=percentage%20%3D%20%5Cfrac%7B1.05%20%5Ctimes%2010%5E%7B-4%7D%7D%7B493%7D%20%5Ctimes%20100)
%
they absorb sunlight and turn it into glucose I think.
The inflated balloon shrinks when it is placed in an ice bath with no change in atmospheric pressure.
<u>Explanation:</u>
When the inflated balloon is subjected to an ice bath, it shrinks. This is due to the fact that smaller volume gets occupied by the air/gas inside the balloon as the temperature decreases. Hence, causes the balloon walls to collapse.
An ice bath also lowers the overall air temperature of the balloon inside. As the temperature decreases, the air molecules move more slowly and with lower energy. Because of the particle's lower energy, their collisions with the walls are not enough to keep the inflated balloon.
Answer:
9 is the number of protons in the fluorine atom (atomic number)
Explanation: