Ask question

Ask question

All categories

4 years ago

12

Weight is measured as the downward force of __________.

1 answer:

Blizzard [7]4 years ago

7 0

Gravity I believe. Hope I helped

You might be interested in

What does each letter stand for in the formula p=v x i?

Nataly_w [17]

I only know P and V and P is pressure and V is volume

6 0

3 years ago

Which of the following includes an example of a chemical property of an element?

Romashka [77]

Answer: D

Explanation:

5 0

3 years ago

what would happen to the size of the shadow if the distance between the light and the hand is increased.

Sergio039 [100]

I don’t think I will have any time to go

8 0

3 years ago

1. What did the hard-boiled egg do when you lifted your finger? Describe your

jenyasd209 [6]

EXPLAINING : The raw egg keeps spinning after you touch it briefly because the liquid egg inside remains in motion, it's inertia is greater than that of the solid interior of the hardboiled egg. An object's momentum is its resistance to changing its state of motion; roughly "how hard it is to stop".

Answer : object's momentum

Please follow me me on youtube Cartoon View maker (US)

6 0

2 years ago

Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri

Ainat [17]

Answer:

The taken is $t_A = 19.0 \ s$

Explanation:

Frm the question we are told that

The speed of car A is $v_A = 22 \ m/s$

The speed of car B is $v_B = 29.0 \ m/s$

The distance of car B from A is $d = 300 \ m$

The acceleration of car A is $a_A = 2.40 \ m/s^2$

For A to overtake B

The distance traveled by car B = The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is

$d = v_B * t_A$

Where $t_B$ is the time taken by car B

Now this can also be represented as using equation of motion as

$d = v_A t_A + \frac{1}{2}a_A t_A^2 - 300$

Now substituting values

$d = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

Equating the both d

$v_B * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

substituting values

$29 * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300$

$7 t_A =1.2 t_A^2 - 300$

$1.2 t_A^2 - 7 t_A - 300 = 0$

Solving this using quadratic formula we have that

$t_A = 19.0 \ s$

7 0

3 years ago