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Harlamova29_29 [7]

3 years ago

7

A computer with a resistance of 52.7 Ω has a power input of 210.0 W. Calculate the current in the computer. Round your answer to

the nearest whole number.

2 answers:

Scrat [10]3 years ago

8 0

2.00 A

they want me to put an explanation but im not bout to do that uhnuhn

coldgirl [10]3 years ago

5 0

The correct answer is 2.00 A

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A jet ski accelerates towards a ramp at 2.5 m/s/s for 35 s until it finally flies off the water. Determine the

zlopas [31]

Answer:

1531 m

Explanation:

The motion of the jet ski is an uniformly accelerated motion, so we can find the distance travelled by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For the jet ski in this problem,

$a=2.5 m/s^2$

t = 35 s

u = 0 (it starts from rest)

Solving for s, we find the distance travelled:

$d=0+\frac{1}{2}(2.5)(35)^2=1531 m$

8 0

3 years ago

What is kinematics???

dalvyx [7]

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

7 0

2 years ago

Read 2 more answers

The box as shown above is moving at a constant velocity . True or false

STatiana [176]

True because on side is heavier than the other

8 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the shap

AURORKA [14]

Answer: The height of the pile increasing is increasing at $0.16\frac{ft}{min}$

Explanation:

Given

Rate at which gravel is being dumped , $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

=>Rate of increase of volume of cone= $\frac{\mathrm{d} V}{\mathrm{d} t}=10\frac{ft^{3}}{min}$

If height of the cone at any instant is h then the diameter of cone is also h

Volume of cone , $V=\frac{\pi r^{2}h}{3}=\frac{\pi h^{3}}{4\times 3}=\frac{\pi h^{3}}{12}$

Now differentiate both sides w.r.t time(t)

$\frac{\mathrm{d} V}{\mathrm{d} t}=\frac{\pi h^{2}}{4}\frac{\mathrm{d} h}{\mathrm{d} t}$

Therefore at h = 9 ft

$10=\frac{\pi \times 9^{2}}{4}\times \frac{\mathrm{d} h}{\mathrm{d} t}$

=> $\frac{\mathrm{d} h}{\mathrm{d} t}=0.16\frac{ft}{min}$

Thus the height of the pile increasing is increasing at $0.16\frac{ft}{min}$

6 0

3 years ago

How much time would it take a fox to accelerate from 2 m/s to 8 m/s at a rate of 2 m/s/s?

faltersainse [42]

Answer:

read below

Explanation:

uh I might be crazy but there is two ways to solve this a simple way and complexish first understand you are using kinematic equations all 4 are valid for this but you need to know which ones the best choice which is vf=vi + at this should solve for time i would do it for you but I find it better when you plug it in your self your learn much better

3 0

3 years ago