Answer: __________________________________________________ No; the sample could not be aluminum; since the density of aluminum, " 2.7 g/cm³ " , is NOT close enough to the density of the sample, " 3.04 g/cm³ " . ________________________________________________ Explanation: ________________________________________________ Density is expressed as "mass per unit volume" ;
in which: "mass, "m", is expressed in units of "g" (grams); and: "Volume, "V", is expressed in units of "cm³ " (such as in this problem); or in units of "mL" ; __________________________________________________ {Note the exact conversion: " 1 cm³ = 1 mL " .}. __________________________________________________ The formula for density: D = m/V ;
Given: The density of aluminum is: 2.7 g/cm³.
Given: A sample has a mass of 52.0 g ; and Volume of 17.1 cm³ ; could it be aluminum? _________________________________________________________ Let us divide the mass of the sample by the volume of the sample; by using the formula: ___________________________________________ D = m / V ;
and see if the value is at, or very close to "2.7 g/cm³ ".
If it is, then it could be aluminum. ____________________________________________________ The density for the sample:
D = (52.0 / 17.1) g/cm³ = 3.0409356725146199 g/cm³ ; →round to "3 significant figures" ; = 3.04 g/cm³ . _______________________________________________ No; the sample could not be aluminum; since the density of aluminum, "2.7 g/cm³ " is NOT close enough to the density of the sample, "3.04 g/cm³ " . ____________________________________________________
