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pochemuha
3 years ago
11

Two friends of different masses are on the playground. They are playing on the seesaw and are able to balance it even though the

ir masses are different.
How are they able to balance on the seesaw?

1) They are able to balance torques due to gravity.
2) They are able to balance their respective energies.
3) All of these.
4) Their densities are the same.
5) They are able to balance forces due to gravity.
6) They are able to balance their respective momenta.
Physics
1 answer:
Svetradugi [14.3K]3 years ago
6 0
1) They are able to balance the torques due to gravity.

The torque is equal fo Force * lever arm.

The force downward is due to gravity, Force = mass*gravity.

Then the heavier student will produce a bigger force downgar and he/she shall shorten the lever arm of his/her side, by placing himself closer to the rotation axis, than the lighter student.

 
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Over the past 100 years earths temperature
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Answer:

<u>Over the last century, the average surface temperature of the Earth has increased by about 1.0o F.</u>

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Which is a diatomic molecule? <br> A. Ar <br> B. CO <br> C. CO2 <br> D. NaCl
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Answer: B. CO

Explanation:

Diatomic molecules are those that are formed by two atoms of the same chemical element (homonuclear diatomic molecule) or different chemical element (heteronuclear diatomic molecule).  

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3 0
2 years ago
. A person weighing 750 N gets on an elevator.
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F = 750 N  (Force)

d = 10 m  (displacement )

t = 25 s   (time)

L = ?   (Mechanical work )  =  (Energy)

P = ?   (Power)

Solve:

L = F × d = 750 × 10 = 7500 Joules

P = L / t = 7500 / 25 = 300 Watts

5 0
2 years ago
Why does gas have the most energy but moves the slowest
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4 0
2 years ago
A truck with a heavy load has a total mass of 7100 kg. It is climbing a 15∘ incline at a steady 15 m/s when, unfortunately, the
Andrej [43]

Answer:

The load has a mass of 2636.8 kg

Explanation:

Step 1 : Data given

Mass of the truck = 7100 kg

Angle = 15°

velocity = 15m/s

Acceleration = 1.5 m/s²

Mass of truck = m1 kg

Mass of load = m2 kg

Thrust from engine = T

Step 2:

⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:

T = (m1+m2)*g*sinθ

⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes  m1*gsinθ .

Resultant force on truck is F = T – m1*gsinθ  

F causes the acceleration of the truck: F= m*a

This gives the equation:

T – m1*gsinθ = m1*a  

T = m1(a + gsinθ)

Combining both equations gives:

(m1+m2)*g*sinθ = m1*(a + gsinθ)

m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ

m2*g*sinθ = m1*a

Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:

m2*g*sinθ = (7100 – m2)*a

m2*g*sinθ = 7100a – m2a

m2*gsinθ + m2*a = 7100a

m2* (gsinθ + a) = 7100a

m2 = 7100a/(gsinθ  + a)

m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)

m2 = 2636.8 kg

The load has a mass of 2636.8 kg

6 0
2 years ago
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