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joja [24]
3 years ago
11

A goose is flying south for the winter at a constant speed. Keep in mind that one mile is 1.61 km, and one pound is 454 g.The go

ose has a mass of 20.1 lb and is flying at 9.60 miles/h. What is the kinetic energy of the goose in joules?
Chemistry
1 answer:
ruslelena [56]3 years ago
8 0

Answer:

kinetic energy =  84.0260 joules

Explanation:

given data

one mile = 1.61 km

one pound = 454 g

mass = 20.1 lb = 9.1172 kg

flying velocity = 9.60 miles/h = 9.60 × 1.61 × \frac{5}{18} = 4.2933 m/s  

solution

we get here kinetic energy that is express as

kinetic energy = 0.5 × m × v²   .........................1

put here value and we get

kinetic energy = 0.5 × 9.1172 × 4.2933²

kinetic energy =  84.0260 joules

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Examples of scenarios that would adhere to the law of conservation of energy are as follows:

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<h3>What is law is conservation of energy?</h3>

The law of conservation of energy states that energy cannot be created nor destroyed but is conserved when it is transferred from one form to another.

The law of conservation of energy is obeyed by majority of natural and artificial systems. For example;

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2 years ago
How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose
Aliun [14]

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

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