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Liula [17]
2 years ago
14

How far should pencil held from a convex mirror of radius 80 cm to form an image one-half the size of the pencil?

Physics
1 answer:
prisoha [69]2 years ago
4 0

Answer:

10.0

Explanation:

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Once the crate in sample problem 4C is in motion, a horizontal force of 53 N keeps the crate moving with a constant velocity. Fi
liraira [26]

Answer: k = 5.4kg/m

where m is the mass of the crate.

Explanation:

The force of kinetic friction is described by the equation:

Ff = k*N

in the opposite direction in wich the object moves, where k is the coefficient of kinetic friction and N is the normal force, that is equal to the weight of the crate. N = m*g where m is the mass of the crate and g is the gravitational acceleration.

If the crate keeps moving with constant velocity, this means that the crate is not accelerating so there is no net force applied on the crate. Then the friction force should be equal in magnitude to the horizontal force of 53N (but with different sign)

then we have:

k*m*g =  53N

k*m = 53N/9.8m/s^2 = 5.4kg

k = 5.4kg/m

In the question we do not have the mass of the crate, so you must put the value in that equation to get the value of k.

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2 years ago
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frosja888 [35]
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2 years ago
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I need help with #24 ASAP .. I have to get it done today
SOVA2 [1]

Answer:

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2 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
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Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

x - x₀ = 40100 m

Find: a and t

(47.5)² = (34.3)² + 2a(40100)

a = 0.0135 m/s²

40100 = ½ (47.5 + 34.3)t

t = 980 s

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3 years ago
Streak is a reliable identifier of a mineral. true or false
inysia [295]

Answer:

true?

Explanation:

Im positive but not 100% sure wait for someone else to answer and see if they say the same.

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