Answer:
Explanation:
To solve this problem we use the formula for accelerated motion:
We will take the initial position as our reference (
) and the downward direction as positive. Since the rock departs from rest we have:
Which means our acceleration would be:
Using our values:
the axis acts against and it would be a contact force
Answer:
0.3 m
Explanation:
Initially, the package has both gravitational potential energy and kinetic energy. The spring has elastic energy. After the package is brought to rest, all the energy is stored in the spring.
Initial energy = final energy
mgh + ½ mv² + ½ kx₁² = ½ kx₂²
Given:
m = 50 kg
g = 9.8 m/s²
h = 8 sin 20º m
v = 2 m/s
k = 30000 N/m
x₁ = 0.05 m
(50)(9.8)(8 sin 20) + ½ (50)(2)² + ½ (30000)(0.05)² = ½ (30000)x₂²
x₂ ≈ 0.314 m
So the spring is compressed 0.314 m from it's natural length. However, we're asked to find the additional deformation from the original 50mm.
x₂ − x₁
0.314 m − 0.05 m
0.264 m
Rounding to 1 sig-fig, the spring is compressed an additional 0.3 meters.
Answer:
correct answer is Fall slide, slump, creep, flow
Explanation:
solution
we know that Movement of particle under the influence of gravity
so rock and other material move down as gravity.
first rock particle fall down because falls occur very rapidly with high slope after that they slide on the slope and after sliding they slump and it occurs when the rupture surface is curved after slump process they creep.
after creeping, it can flow particle as it occurs slowly with the low slope with water.
so correct answer is Fall slide, slump, creep, flow
