Question

Two long straight wires lie parallel to each other 2.00 cm apart, and carry equal and opposite currents of 145 A. What is the strength of the magnetic field they produce, halfway between them

Answer 1

Answer:

B = 2.9 mT

Explanation:

Given that,

The distance between the wires, r = 2 cm

Distance halfway between them d = 1 cm = 0.01 m

The current in the wires, I = 145 A

We need to find the strength of the magnetic field they produce, halfway between them. The formula for the magnetic field in the wire is given by :

$B=\dfrac{\mu_o I}{2\pi d}\\\\B=\dfrac{4\pi \times 10^{-7}\times 145}{2\pi \times 0.01}\\\\B=2.9\ mT$

So, the required magnetic field is 2.9 mT.