All categories

3 years ago

~choices below~

2 answers:

6 0

Answer : The correct option is, (A) Physical properties can be observed without changing the identity of the substance, while chemical properties can not.

Explanation :

Physical properties : It can be observed or measured without changing the chemical property of the substance.

In the physical property, no new compound or substance is formed only changes occur in the phase.

Chemical properties : It can be observed or measured by changing the chemical property of the substance.

In the chemical property, a new compound or substance is formed and no changes occurs in the phase.

Hence, the correct option is, (A)

mart [117]3 years ago

5 0

A is the correct answer

You might be interested in

We can classify both the shovel and the garden trowel as compound machines. This is because each garden tool contains two simple

Roman55 [17]

Hello,

I believe they are a lever and a wedge.

I hope this helps!

6 0

3 years ago

Read 2 more answers

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie

leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

$MV=mv$

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

$V = \frac{mv}{M}$

Also we have that $m/M = 1/7 times$

On the other hand we have from law of conservation of energy that

$W_f = KE$

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

$F_f*S = \frac{1}{2}MV^2$

$\mu M*g*S = \frac{1}{2}MV^2$

$\mu g*S = \frac{1}{2}( \frac{mv}{M})^2$

$\mu = \frac{1}{2} (\frac{1}{7}v)^2$

$\mu = \frac{1}{98}v^2$

$\mu = \frac{1}{g(98)(5.1)}v^2$

Here we can apply the law of conservation of energy for light mass, then

$\mu mgs = \frac{1}{2} mv^2$

Replacing the value of $\mu$

$\frac{1}{g(98)(5.1)}v^2 mgs = \frac{1}{2}mv^2$

Deleting constants,

$s= \frac{(98*5.1)}{2}$

$s = 249.9m$

7 0

3 years ago

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti

Andreas93 [3]

Answer: 1.88 N

Explanation:

Data:

Force = 4.00N
angle = 62°
horizontal force = ?

Solution:

The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.

That ratio is:

                        horizontal - leg
cos(angle) = -------------------------
                          hypotenuse

So, applied to the force, that is:

                             horizontal force
cos (angle) = -----------------------------------
                                 total force

So, clearing the horizontal component you get:

horizontal force = force * cos (angle)

Substitute the data given:

horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N

Answer: 1.88N

7 0

2 years ago

Read 2 more answers

QUICK SOMEONE PLEASE HELP!!!! I’LL MARK BRAINLIEST!!!

Brilliant_brown [7]

Temperatures above 100 are gases

8 0

3 years ago

If the velocity of an object is zero at one instant, what is true about the acceleration of that object

Charra [1.4K]

Answer:

I. The acceleration could be positive.

II. The acceleration could be zero.

III. The acceleration could be negative.

Explanation:

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

$Velocity = \frac{distance}{time}$