Explanation:
When,the vehicle has uniform velocity, it's acceleration becomes zero
The answer is:
V = d/t d = 86 km t = 1.3 hrs
V = 86 km/ 1.3 hrs
V = 66.15 km/ hrs
I hope this helps!!
Answer:
2.47 m
Explanation:
Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.
The horizontal velocity of the ball is constant:

and the time taken to cover the horizontal distance d is

So this is the time the ball takes to reach the horizontal position of the crossbar.
The vertical position of the ball at time t is given by

where
is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration of gravity
And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:

The height of the crossbar is h = 3.05 m, so the ball passes

above the crossbar.
Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 4.7 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (4.7 s) + ½ (9.8 m/s²) (4.7 s)²
Δy ≈ 110 m