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Snezhnost [94]
3 years ago
5

Lifting a box off the floor is an example of what type of force?

Physics
2 answers:
s2008m [1.1K]3 years ago
8 0
Gravitational I think would be the answer, Hope this helps!
goldenfox [79]3 years ago
6 0
<span>Applied Force. Applied force is a force that is applied to an object by a person or another object</span>
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A book is sitting on a desk. What best describes the normal force acting on the book?
Marat540 [252]

Explanation:

in my opinion I'd say it's gravity because it's making the book stay in it's one and only position pulling the book at the center of the desk

4 0
3 years ago
Read 2 more answers
How much Nitrogen (N) atoms are in this 3NH4Cl?
mihalych1998 [28]

Answer:

3

Explanation:

7 0
3 years ago
In moving out of a dormitory at the end of the semester, a student does 1.20 x 104 J of work. In the process, his internal energ
Zielflug [23.3K]

Answer:

(a) W=1.20×10⁴J

(b) U= -5.46×10⁴J

(c) Q= -4.26×10⁴J

Explanation:

Given that student does 1.20×10⁴J work

(a) W=1.20×10⁴J

Work done by student,so positive sign

During the process, his internal energy decreases by 5.46×10⁴J.

(b) U= -5.46×10⁴J.

As the Energy decreases therefore negative sign

For (c) Q

We know the formula

Q=W+U\\Q=1.2*10^{4}+(-5.46*10^{4} )\\ Q=-4.26*10^{4}J

8 0
3 years ago
Para el siguiente conjunto de medidas, calcule EL ERROR RELATIVO PORCENTUAL: 1.34 m, 1.35 m, 1.37 m y 1.36 m
ivanzaharov [21]

Answer:

Ver explicacion abajo

Explanation:

En este caso para poder calcular el error relativo porcentual, es necesario calcular primero el error absoluto, que se calcula de la siguiente forma:

Error absoluto = Resultado exacto - aproximación

Sin embargo, no tenemos el resultado exacto de las medidas, pero podriamos conocerlo tomando el promedio de estas medidas y este es el que tomaremos como el verdadero resultado de las medidas:

Promedio de medidas = 1.34 + 1.35 + 1.37 + 1.36 / 4

Promedio de medidas = 1.355 m

Ya que tenemos el promedio, podemos calcular el error absoluto de cada medida y luego el error relativo porcentual:

Ea1 = 1.355 - 1.34 = 0.015

Ea2 = 1.355 - 1.35 = 0.005

Ea3 = 1.37 - 1.355 = 0.015

Ea4 = 1.36 - 1.355 = 0.005

Ya que tenemos los 4 errores absolutos, es posible calcular el porcentual:

%error relativo = (Error absoluto / resultado exacto) * 100

Aplicando la expresión con cada uno de los valores tenemos:

%Er1 = (0.015/1.34) * 100 = 1.12%

%Er2 = (0.005/1.35) * 100 = 0.37%

%Er3 = (0.015/1.37) * 100 = 1.09%

%Er4 = (0.005/1.36) * 100 = 0.37%

Espero que te sirva.

4 0
3 years ago
What is the force of an object with a mass of 30 kg that is free falling?
disa [49]

Answer:

F = 294.3 [N]

Explanation:

To solve this problem we must use Newton's second law which tells us that force is equal to the product of mass by acceleration. It is this particular case the acceleration is due to the gravitational acceleration since the body is in free fall.

Therefore we have:

F = m*g

where:

F  = force [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s^2]

F = 30*9.81

F = 294.3 [N]

4 0
3 years ago
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