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3 years ago

What is the difference between mass and weight?

Physics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Answer:

C. Mass is independent of the force acting on the mass.

Weight depends on the gravitational force acting on the mass.

Example: A mass of 1 kg on the earth still has a mass of 1 kg on the moon;

whereas the weight of that mass on earth is 9.8 N and only 1/6 of that amount on the moon.

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A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s

sergey [27]

Answer:

Y = V / f where Y equals wavelength

4 Y1 = V / f1 for a closed pipe the wavelength is 1/4 the length of the pipe

2 Y2 = V / f2 for the open pipe the wavelength is 1/2 the length of the pipe

Y1 / Y2 = 2 = f2 / f1 dividing equations

f2 = 2 f1

the new fundamental frequency is 2 * 130.8 = 261.6

(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.

8 0

3 years ago

Forces affect motions in living and nonliving things. In a human, swallowed food moves down the esophagus into the stomach, even

valina [46]

Answer:

figured it out its d the last one

4 0

2 years ago

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

dedylja [7]

Answer:

Magnitude of net force will be 432.758 N

Explanation:

We have given x component of acceleration $a_x=760m/sec^2$

And vertical component of acceleration $a_y=770m/sec^2$

Mass of the ball m = 0.40 kg

So net acceleration $a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2$

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0

3 years ago

A bike, a truck, and a train—all without passengers, motors, or engines—roll down the same hill. Put the vehicles in order from

Pepsi [2]

Answer: WAIT WHATTTT i have that same test due today and the answer is in explanation

Explanation:

Bike, truck train. we are in the same school i think. Its imma say the incisal JMES Im Lusi i used to help in the library

4 0

3 years ago

(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W

Kitty [74]

Answer:

The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

Explanation:

Given that,

Wavelength = λ

For D to be small,

We need to calculate the minimum width

Using formula of minimum width

$D\sin\theta=n\lambda$

$D=\dfrac{n\lambda}{\sin\theta}$

Where, D = width of slit

$\lambda$ = wavelength

Put the value into the formula

$D=\dfrac{n\lambda}{\sin\theta}$

Here, $\sin\theta$ should be maximum.

So. maximum value of $\sin\theta$ is 1

Put the value into the formula

$D=\dfrac{1\times\lambda}{1}$

$D=\lambda$

(b). If the minimum number is 50

Then, the width is

$D=\dfrac{50\times\lambda}{1}$

$D=50\lambda$

(c). If the minimum number is 1000

Then, the width is

$D=\dfrac{1000\times\lambda}{1}$

$D=1000\lambda$

Hence, The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

4 0

3 years ago