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Elenna [48]
2 years ago
15

The objective lens in a microscope with a 17.0 cm long tube has a magnification of -50.0 and the eyepiece has a magnification of

20.0. (a) What is the focal length of the objective? (b) What is the focal length of the eyepiece?
Physics
1 answer:
Bas_tet [7]2 years ago
5 0

Answer:

(a) 0.34 cm

(b) 1.32 cm

Explanation:

Given that, m_{o}=-50

m_{e}=20 cm

And the length of objective lens in a microscope

L=17

And we have d of the eyepiece is 25 cm.

(a) Focal length of the objective is,

f_{o}=-\frac{L}{m_{o} }\\  f_{o}=-\frac{17}{-50} \\f_{o}=0.34 cm

Therefore, objective lens's focal length is 0.34 cm.

(b) Focal length of an eyepiece,

m_{e}=(1+\frac{d}{f_{e} })\\  20=(1+\frac{25}{f_{e} }\\ f_{e}=\frac{25}{19}cm\\ f_{e}=1.32cm

Therefore, eyepiece's focal length is 1.32 cm.

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The fundamental frequency at which the sound of speakers at the microphone produce constructive interference is 801.076458 Hz

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Therefore, by Pythagoras's theorem, the distance from the speaker furthest from the microphone, to the microphone, 'R₂' is given as follows;

R₂ = √(4.50² + 2.00²) = √(24.25) = 4.9244289009 ≈ 4.924

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For constructive interference, R₂ - R₁ =0.4244289 m = n·λ

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