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Lynna [10]
3 years ago
5

Temperatures expressed in the Kelvin scale are ____ higher than temperatures in the Celsius scale?

Physics
1 answer:
Cerrena [4.2K]3 years ago
4 0
Answer: D. 273


Explanation: Celsius temperatures can be negative while kelvin goes down to absolute zero and doesn’t go any lower, thus no negative numbers
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A 1.0 kg football is given an initial velocity at ground level of 20.0 m/s [37° above horizontal]. It gets blocked just after re
brilliants [131]
1) Data:

Vo = 20 m/s
α = 37°
Yo = 0
Y = 3m

2) Questions: V at Y = 3m and X at Y = 3 m

3) Calculate components of the initial velocity

Vox = Vo * cos(37°) = 15.97 m/s

Voy = Vo * sin(37°) = 12.04 m/s

4) Formulas

Vx = constant = 15.97 m/s

X = Vx * t

Vy = Voy - g*t

Y = Yo + Voy * t - g (t^2) / 2

5) Calculate t when Y = 3m (first time)

Use g ≈ 9.8 m/s^2

3 = 12.04 * t - 4.9 t^2

=> 4.9 t^2 - 12.04t + 3 = 0

Use the quadratic equation to solve the equation

=> t = 0.28 s and t = 2.18s

First time => t = 0.28 s.

6) Calculate Vy when t = 0.28 s

Vy = 12.04 m/s  - 9.8 * 0.28s = 9.3 m/s

7) Calculate V:

V = √ [ (Vx)^2 + (Vy)^2 ] = √[ (15.97m/s)^2 + (9.30 m/s)^2 ] = 18.48 m/s

tan(β) = Vy/Vx = 9.30 / 15.97 ≈ 0.582 => β ≈ arctan(0.582) ≈ 30°

Answer: V ≈ 18.5 m/s, with angle ≈ 30°

8) Calculate X at t = 0.28s

X = Vx * t = 15.97 m/s * 0.28s = 4,47m ≈ 4,5m

Answer: X ≈ 4,5 m
4 0
3 years ago
What part of an electric circuit are the wires that carry the electric current
bezimeni [28]

Answer:

okay so, An electric circuit is a closed loop through which current can  actually flow. All electric circuits must have a voltage source, for example a battery, and a conductor, which is usually  a wire.

how does it flow or how does .current flow in a circuit ? When a wire is connected to battery terminals which is electrons, electrons flow from negative to positive. Electrons have a negative charge in case you didnt know. they are repelled from the negative and attracted to the positive.

if this helped please mark this as brainliest!!! :)

8 0
4 years ago
The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop
nalin [4]

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration a= -4.20 m/s^2

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

0 =24.0 +(-4.20)\times t

t = \dfrac{-24.0}{-4.20}

t=5.71\ sec

Hence, The time is 5.71 sec.

5 0
4 years ago
on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. what is the velocity (speed and direction)
kiruha [24]

Velocity is the rate of change of position of an object. The velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

<h3>What is Velocity?</h3>

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Given that on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. Therefore, the velocity of the air relative to the runner can be written as,

Relative velocity = √[(Velocity of the jogger)² + (Velocity of the air)²]

                            = √[(5)² + (5)²]

                            = √(25 + 25)

                            = √50

                            = 5√2 m/sec

The direction of the relative velocity is,

The angle of relative Velocity = Tan(θ)

Tan(θ) = Vertical velocity / Horizontal velocity

Tan(θ) = 5/5

Tan(θ) = 1

θ = tan⁻¹(1)

θ = 45°

Since this angle is formed between the two velocities, therefore, the direction of the velocity is southwest.

Hence, the velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

Learn more about Velocity here:

brainly.com/question/18084516

#SPJ4

4 0
1 year ago
24. A car is travelling along an expressway at 90 km/h. The driver spots a stalled car and some traffic congestion on the road a
Klio2033 [76]

Answer:

See explanation

Explanation:

We convert the speed of the car to ms-1

90 × 1000/3600 = 25 ms-1

a) from;

F= ma

a= F/m

a= 8400/1050 = 8 ms-2

b) from

v= u - at

v= 0

u = 25 ms-1

a= 8 ms-2

t= ?

t = u/a = 25/8 = 3.1 s

From;

v^2 = u^2 - 2as

v= 0 ms-1

u^2 = 2as

s = u^2/2a

s= (25)^2/2 × 8

s= 625/16

s = 39 m

7 0
3 years ago
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