40:10=12:3
Solution:
Since
40 : 10 = 12 : X
Then we know
10/40 = X/12
Multiplying both sides by 12 cancels on the right
12 × (10/40) = (X/12) × 12
12 × (10/40) = X
Then solving for X
X = 12 × (10/40)
X = 3
Therefore
40 : 10 = 12 : 3
A + b + c = 12
c = (a + b) - 2.....c - a - b = -2
3a + 1 = 2c
add the first 2 equations
a + b + c = 12
-a - b + c = -2
------------------add
2c = 10
c = 5 <== longest side is 5
sub in 5 for c in the 3rd equation
3a + 1 = 2c
3a + 1 = 2(5)
3a + 1 = 10
3a = 10 - 1
3a = 9
a = 3 <== shortest side
now sub in 5 for c and 3 for a back into the first equation
a + b + c = 12
3 + b + 5 = 12
b + 8 = 12
b = 12 - 8
b = 4 <== other side
Answer:
Step-by-step explanation:
15+x=16x+60
Answer: B) No; the remainder is 234, so (x+3) is not a factor.
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Explanation:
We'll use the remainder theorem. That theorem says if we divide p(x) over (x-k), then the remainder is p(k). A special case of this theorem says that if we get 0 as the remainder, then (x-k) is a factor of p(x).
We're dividing f(x) over (x+3) which means that k = -3. Think of x+3 as x-(-3) so you can match it up with the form x-k.
To find the remainder of f(x)/(x+3), we need to compute f(-3).
Plug x = -3 into the f(x) function to get...
f(x) = 4x^3 + 11x^2 - 75x + 18
f(-3) = 4(-3)^3 + 11(-3)^2 - 75(-3) + 18
f(-3) = 234
The remainder is 234, which is isn't zero, so (x+3) is not a factor of f(x).