A girl flies a kite at a height of 500 ft, the wind carrying the kite horizontally away from her at a rate of 20 ft/sec. How fas
t must she let out the string when the kite is 700 ft away from her? ft/sec
1 answer:
Answer:
she must let out the string when the kite is 700 ft away from her at 20 ft/s
Explanation:
given information:
a = the distance between the girl
b = the length of the string
a = 300
da/dt = 20 ft/s
c =500 ft, dc/dt = ?
Pythagorean Theorem,

when y = 500

a = 
= 400
thus

2a da/dt = 2c dc/dt
a da/dt = c dc/dt
400 (25) = 500 dc/dt
dc/dt = 1000/500
= 20 ft/s
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