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Viktor [21]
3 years ago
9

A girl flies a kite at a height of 500 ft, the wind carrying the kite horizontally away from her at a rate of 20 ft/sec. How fas

t must she let out the string when the kite is 700 ft away from her? ft/sec
Physics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

she must let out the string when the kite is 700 ft away from her at 20 ft/s

Explanation:

given information:

a = the distance between the girl

b = the length of the string

a = 300

da/dt = 20 ft/s

c =500 ft, dc/dt = ?

Pythagorean Theorem,

a^{2} + 300^{2}= c^{2}

when y = 500

a^{2} + 300^{2}= 500^{2}

a = \sqrt{500^{2} - 300^{2}}

  = 400

thus

a^{2} + 300^{2}= c^{2}

2a da/dt = 2c dc/dt

a da/dt = c dc/dt

400 (25) = 500 dc/dt

dc/dt = 1000/500

         = 20 ft/s

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