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jeka94
3 years ago
10

Describe some tests that could be done to determine what an unknown substance is.

Physics
2 answers:
valentina_108 [34]3 years ago
6 0

Answer:

Simple chemical tests can be used to identify the presence of various elements or classes of molecules (Tollen's test). ... Electron spin resonance (ESR): Also referred to as electron paramagnetic resonance (EPR), this method uses the spins of unpaired electrons in molecules to determine structure

natima [27]3 years ago
3 0

Answer:

by finding melting and boiling points

Explanation:

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2). If you record a wave going 4m/s and the Period of the wave was<br> 60s, how long was the wave?
Taya2010 [7]

Answer:240 meters

Explanation:60×4

8 0
3 years ago
When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries?
Ket [755]

Answer:

Explanation:

Assume that a single baby cries at X db

4 babies crying would be X + 10log₁₀(4) = X + 6 db

8 0
2 years ago
Buoyancy is a force that always acts in an
Margarita [4]

Buoyancy is a force that always acts in an upward direction exerted by a fluid on a body placed in the fluid

Hope this helps :)

7 0
3 years ago
Read 2 more answers
Two moles of helium are initially at a temperature of 21.0 ∘Cand occupy a volume of 3.30×10−2 m3 . The helium first expands at c
Anettt [7]

Answer:

(B) The total internal energy of the helium is 4888.6 Joules

(C) The total work done by the helium is 2959.25 Joules

(D) The final volume of the helium is 0.066 cubic meter

Explanation:

(B) ∆U = P(V2 - V1)

From ideal gas equation, PV = nRT

T1 = 21°C = 294K, V1 = 0.033m^3, n = 2moles, V2 = 2× 0.033=0.066m^3

P = nRT ÷ V = (2×8.314×294) ÷ 0.033 = 148140.4 Pascal

∆U = 148140.4(0.066 - 0.033) = 4888.6 Joules

(C) P2 = P1(V1÷V2)^1.4 =148140.4(0.033÷0.066)^1.4= 148140.4×0.379=56134.7 Pascal

Assuming a closed system

(C) Wc = (P1V1 - P2V2) ÷ 0.4 = (148140.4×0.033 - 56134.7×0.066) ÷ 0.4 = (4888.6 - 3704.9) ÷ 0.4 = 1183.7 ÷ 0.4 = 2959.25 Joules

(C) Final volume = 2×initial volume = 2×0.033= 0.066 cubic meter

6 0
3 years ago
Why are infrared waves located between microwaves and visible light on the electromagnetic spectrum?
dangina [55]

Answer: The infra red waves is located between microwave and visible light based on their WAVELENGTH and FREQUENCY of occurrence.

Explanation:

Electromagnetic waves are those waves that do not require or need a material medium for its propagation, but they are able to travel through a vacuum. They exhibit or show all properties associated or connected with light. They are undeflected in electric and magnetic fields. These electromagnetic waves are arranged in order of their FREQUENCY and WAVELENGTHS which is known as ELECTROMAGNETIC SPECTRUM.

FREQUENCY is defined as the number of cycles which the wave completes in one second and is measured in Hertz(Hz). While WAVELENGTH is defined as the distance between two successive crests or troughs of waves which is measured in meter (m).

The electromagnetic spectrum is made up of the following rays which is arranged from the biggest wavelengths to the smallest:

--> Radiowaves

--> microwave :

--> infrared rays:

--> visible light:

--> ultraviolet rays

--> x-rays and

--> Gamma rays.

According to the arrangement of the spectrum above, the microwave has a higher wavelength and frequency than the infrared rays, while the visible light has a lower wavelength and frequency than the infrared rays.

3 0
3 years ago
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