Question

The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

Answer 1

The electrical force acting on a charge q immersed in an electric field is equal to
$F=qE$
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
$E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C$