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3 years ago

The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

1 answer:

5 0

The electrical force acting on a charge q immersed in an electric field is equal to
$F=qE$
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
$E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C$

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Which of the following are examples of both projectile motion and 2-dimensional motion?

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3 years ago

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Real bodies emit and absorb more radiation than a blackbody at the same temperature. True or False

monitta

Answer: False

Explanation:

Relative to the concept of radiations, a black body is an object capable of absorbing any form of electromagnetic radiation irrespective of its frequency or angle of incidence when incident on such object.

However, the same cannot be said about real bodies as real bodies are those which reflect all rays incident on them completely and uniformly in all directions.

One very important characteristic of black bodies is that they are ideal emmiters.

The concept of emmisivity is brought about by the existence of real bodies .

This is due to the fact that they are only able to emit radiation at a fraction of the black body energy levels.

Please note that by convention, the emmisivity of a real body is always less thaan 1.

As such they are not able to emit as much radiation as a black body at the same temperature.

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3 years ago

An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3

Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

$v = u+at$

$t = \dfrac{v-u}{a}$

Put the value into the formula

$t = \dfrac{80-0}{3}$

$t =26.67\ sec$

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s = 0+\dfrac{1}{2}\times3\times(26.67)^2$

$s =1066.9\ m$

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

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2 years ago

The second ionization energy is the energy required to remove the _______ Electron after a __________ one has been removed.

Sindrei [870]

The second ionization energy is the energy required to remove the <u>second </u>electron after a <u>valence</u> one has been removed.

<h3><u>Explanation:</u></h3>

For an element, the first ionization energy is defined as the amount of energy required to remove one electron from the outermost valence shell of a neutral atom. Removing one electron increases the number of protons, making it a 1+ ion.

The nucleus (protons) has more bonding to the electrons with negative charge and thus more energy is required if another electron needs to be removed. This higher energy required to remove second electron from a 1+ ion (after the first one has been removed) is termed as the second ionization energy. Second ionization energy leads to formation of a 2+ ion. Similarly, third ionization energy is higher than second ionization energy.

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3 years ago

A car speeds past you sounding its horn at a frequency of 1000Hz. The frequency you hear:

ki77a [65]

Answer:

f' =1064.1025 Hz

Explanation:

We know that from doppler's effect

$f'=\frac{v+v_0}{v-v_s}f$

f'= observed frequency

f= actual frequency =1000 Hz

v= velocity of sound waves = 332 m/s

v_o= velocity of observer =0

v_s= velocity of source. ( let velocity of car be 20 m/s)

therefore,

$f'=\frac{332+0}{332-20}\times1000$

f' =1064.1025 Hz

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3 years ago