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irina1246 [14]
3 years ago
14

Hemoglobin, the oxygen-carrying protein in red blood cells, has four iron atoms per molecules ad contains 0.340 percent iron by

mass. calculate the molar mass of hemoglobin
Chemistry
1 answer:
Lelu [443]3 years ago
8 0
Molar mass of a compound is the equivalent mass of the compound per mole of it. To determine the molar mass of hemoglobin, we need to know the mass and the number of moles that is present in a certain sample. We make use of the values given above.
Given
0.340 percent Fe = 0.340 g Fe / 100 g hemoglobin
4 atoms Fe per 1 molecule of hemoglobin

Solution:
4 atoms Fe per 1 molecule of hemoglobin ( 1 mol Fe / 6.022 x10^23 atoms Fe) ( 55 .85 g Fe/ 1 mol Fe ) ( 6.022x10^23 molecule hemoglobin / 1 mol hemoglobin ) = 223.4 g Fe / mol hemoglobin

Molar mass = (100 g hemoglobin / 0.340 g Fe) (223.4 g Fe / mol hemoglobin) = 65705.88 g/mol hemoglobin

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Explanation:

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1. Write the molecular equation, ionic equation, and net ionic equation for the reaction between calcium chloride and ammonium p
aalyn [17]

Answer:

(molecular) 3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

(ionic) 3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)

(net ionic) 3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

Explanation:

The molecular equation includes al the species in the molecular form.

3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

The ionic equation includes all the ions (species that dissociate in water) and the species that do not dissociate in water.

3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the species that do not dissociate in water. In does not include <em>spectator ions</em>.

3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

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Aluminum boils at 2467°C. Aluminum’s boiling point in Kelvin is 2194.<br> T or F
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That is false because aluminum melts at 2,470C
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What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?
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Answer:

3.74 M

Explanation:

We know that molarity is moles divided by liters. The first thing to do here is convert your 1500 mL of solution to L. There's 1,000 mL in 1 L, so you need to divide 1500 by 1000:

1500 ÷ 1000 = 1.50

Now you can plug your values into the equation for molarity:

5.60 mol ÷ 1.50 L = 3.74 M

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