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olchik [2.2K]
3 years ago
9

Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc

ounters no air resistance?
Physics
2 answers:
tamaranim1 [39]3 years ago
5 0

Answer:

50 m/s

Explanation:

u = 0 m/s, t = 5 seconds, v = ? , g = 10 m/s^2

Use first equation of motion

v = u + g t

v = 0 + 10 x 5 = 50 m/s

Tasya [4]3 years ago
3 0

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

V = 98 m/s

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What are some different kinds of bias and how can they ruin a research project
m_a_m_a [10]

Three types of bias can be distinguished: information bias, selection bias, and confounding. These three types of bias and their potential solutions are discussed using various examples.

Bias can damage research, if the researcher chooses to allow his bias to distort the measurements and observations or their interpretation. When faculty are biased about individual students in their courses, they may grade some students more or less favorably than others, which is not fair to any of the students.

4 0
2 years ago
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A man standing on top of a 30 m tall building throws a brick downwards with a velocity of 12 m/s. Determine the speed of the bri
loris [4]

Answer:

27.1m/s

Explanation:

Given parameters:

Height of the building  = 30m

Initial velocity  = 12m/s

Unknown:

Final velocity  = ?

Solution:

We apply one of the kinematics equation to solve this problem:

         v²  = u²  + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

          v²   = 12²  + (2 x 9.8 x 30)

          v  = 27.1m/s

3 0
3 years ago
Water is called the “universal solvent.” Which statement best explains this description with respect to ionic compounds?
Semmy [17]
I think it is c for the answer
6 0
3 years ago
A heavy object and a light object are dropped from the same height. If we neglect air resistance, which will hit the ground firs
Maksim231197 [3]

Answer:

None, both objects will hit ground at the same time.

Explanation:

  • Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:

        \Delta h = \frac{1}{2}*g*t^{2}  (1)

  • As the left side in (1) is the same for both objects, the right side will be the same also.
  • Since g is constant close to the surface of the Earth, it's also the same for both objects.
  • So, the time t must be the same for both objects also.
6 0
3 years ago
A compact disc rotates from rest up to an angular speed of 31.4 rad/s in a time of 0.892 s.
Serggg [28]

Answer:

(a)  α = 35.20 rad/s^2

(b)  θ = 802°

(c)   v = 139.73 cm/s

(d)   a = 156.64 cm/s^2

Explanation:

(a) To find the angular acceleration of the disc you use the following formula:

\alpha=\frac{\omega-\omega_o}{t}         (1)

w: angular speed of the disc = 31.4 rad/s

wo: initial angular speed = 0 rad/s

t: time = 0.892s

You replace the values of the parameters in the equation (1):

\alpha=\frac{31.4rad/s-0rad/s}{0.892s}=35.20\frac{rad}{s^2}

The angular acceleration of the disc, for the given time, is 35.20rad/s^2

(b) To calculate the angle describe by the disc in such a time you use:

\theta=\frac{1}{2}\alpha t^2         (2)

\theta=\frac{1}{2}(35.20rad/s^2)(0.892s)^2=14.00rad

In degrees you have:

\theta=14.00rad*\frac{180\°}{\pi \ rad}=802\°

The angle described by the disc is 802°

(c) To calculate the tangential speed of the microbe for t=0.892s, you use the following formula:

v=\omega r         (3)

w: angular speed for t = 0.892s = 31.4rad/s

r: radius of the disc = 4.45cm

v=(31.4rad/s)(4.45cm)=139.73\frac{cm}{s}

The tangential speed is 139.73 cm/s

(d) The tangential acceleration is calculated by using the following formula:

a=\alpha r

α: angular acceleration for t=0.892s

a=(35.20rad/s^2)(4.45cm)=156.64\frac{cm}{s^2}

The tangential acceleration is 156.64cm/s^2

7 0
3 years ago
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