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olchik [2.2K]
3 years ago
9

Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc

ounters no air resistance?
Physics
2 answers:
tamaranim1 [39]3 years ago
5 0

Answer:

50 m/s

Explanation:

u = 0 m/s, t = 5 seconds, v = ? , g = 10 m/s^2

Use first equation of motion

v = u + g t

v = 0 + 10 x 5 = 50 m/s

Tasya [4]3 years ago
3 0

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

V = 98 m/s

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S ?
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V ?
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S=ut+0.5at^2
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In order for an atom to have a positive charge of +2, it means that there must be 2 protons more than the number of electrons. Since atoms exchange electrons (and not protons), this means that the atom must have "lost" 2 electrons.

In this problem, we have an atom with 13 protons: this means that initially it also has 13 electrons. However, later the atom lost 2 electrons, and as a result, the final charge is +2e.

Learn more about atoms:

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