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sasho [114]
3 years ago
10

A transition metal complex in solution has an absorption peak at 450 nm, in the blue region of the visible spectrum. What color

is this solution?
A) Violet B) Orange C) Green D) Blue

Physics
1 answer:
Ivan3 years ago
7 0

Answer:

In the case of a solution transition metal complex that has an absorption peak at 450 nm in the blue region of the visible spectrum, the (complementary) color of this solution is orange (option B).

Explanation:

The portion of UV-visible radiation that is absorbed implies that a portion of electromagnetic radiation is not absorbed by the sample and is therefore transmitted through it and can be captured by the human eye. That is, in the visible region of a complex, the visible color of a solution can be seen and that  corresponds to the wavelengths of light it transmits, not absorbs. The  absorbing color is complementary to the color it transmits.

So, in the attached image you can see the approximate wavelengths with the colors, where they locate the wavelength with the absorbed color, you will be able to observe the complementary color that is seen or reflected.

<u><em> In the case of a solution transition metal complex that has an absorption peak at 450 nm in the blue region of the visible spectrum, the (complementary) color of this solution is orange (option B).</em></u>

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Genrish500 [490]

Answer:

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

Explanation:

The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by 0.5mv^{2}

Equating

mgh=0.5mv^{2}

Making v the subject of the formula then

v=\sqrt {2gh}

Substituting 9.81 m/s2 for g and 18.5 m for h then the velocity will be

v=\sqrt {2\times 9.81\times 18.5}=19.0517715711689\ m/s\\v\approx 19.05\ m/s

To get the kinetic eneegy, since PE=KE AND KE is

KE=0.5mv^{2}

Substituting v with 19.05 and m with 0.017 kg we have

0.5\times 0.017\times 19.05^{2}=3.08467125/ J\approx 3.08 J

This can also be achieved by mgh since PE=KE hence 0.17*9.81*18.5=3.085245 J and the results are slightly different due to small energy losses and rounding off of values.

7 0
3 years ago
Two rather unequal cars are competing in a drag race. For simplicity, let's assume that the accelerations of the cars are consta
MA_775_DIABLO [31]

Answer:

car1: a=3.1m/s^2 , car2: a=6.1m/s^2

(a) 1/2*3.1*t^2= 1/2*6.1*(t-0.9)^2

1.55t^2= 3.05(t^2-1.8t+0.81)= 3.05t^2-5.49t+2.4705

1.5t^2-5.49t+2.4705= 0

t= 3.13457 = 3.14[s] after.

(b) d= 1/2*3.1*3.13457^2= 15.23[m] approx.

(c) car1: v=at = 3.1*3.13457= 9.717m/s

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4 years ago
A racecar is traveling at a speed of 80.0 m/s on a circular
Simora [160]
A :-) F = mv^2 by r
Given - m = 500 kg
v = 80.0 m/s
r = 450 m
Solution -
F = mv^2 by r
F = 500 x (80)^2 by 450
F = 500 x 6400 by 450
( cut 500 and 450 because 5 x 100 = 5 , 5 x 90 = 450 and also 90 and 6400 because 90 x 70 = 6400 )
F = 100 x 70
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The correct answer is:

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alekssr [168]
School psychologist
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