<span>t^2 = 1/4.9 </span>
<span>t = 0.45 sec
answer:</span><span>1 - 4.9t^2 = 0 </span>
The response is False, both bars, iron bars and plastic
bars have de same inertia, this characteristic does not depend on the type of
material, the inertia depends on his transverse section, since we can estimate
in the following formula
<span>Area moment of inertia Ixx = BH3/12</span>
<span>Area moment of inertia Iyy= HB3/12</span>
The answer is A.) The ratio of thier masses is always the same
Answer:
![f=272.15Hz](https://tex.z-dn.net/?f=f%3D272.15Hz)
Explanation:
Given data
Length of tube L=0.632 m
Speed of sound v=344 m/s
To find
Fundamental frequency f
Solution
The fundamental frequency of the tube can be given as:
![f=\frac{v}{2L}\\ f=\frac{344m/s}{2(0.632m)}\\ f=272.15Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B2L%7D%5C%5C%20f%3D%5Cfrac%7B344m%2Fs%7D%7B2%280.632m%29%7D%5C%5C%20f%3D272.15Hz)
Answer:
<em>The magnitude of the force is 10 N</em>
Explanation:
<u>Coulomb's Law</u>
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
![\displaystyle F=k\frac{q_1q_2}{d^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3Dk%5Cfrac%7Bq_1q_2%7D%7Bd%5E2%7D)
Where:
![k=9\cdot 10^9\ N.m^2/c^2](https://tex.z-dn.net/?f=k%3D9%5Ccdot%2010%5E9%5C%20N.m%5E2%2Fc%5E2)
q1, q2 = the objects' charge
d= The distance between the objects
We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:
![\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3D9%5Ccdot%2010%5E9%5Cfrac%7B1%2A1%7D%7B30000%5E2%7D)
![\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3D9%5Ccdot%2010%5E9%5Cfrac%7B1%2A1%7D%7B30000%5E2%7D)
F = 10 N
The magnitude of the force is 10 N