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3 years ago

C) Explain the following.Keftles, cooking pans and iron boxes have polished surfaces

Physics

1 answer:

Monica [59]3 years ago

5 0

Answer:

Polished surfaces reduce heat loss

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A wave has a wavelength of 12 mm and a frequency of 7 hertz. What is its speed?

IRISSAK [1]

V = wavelength * frequency
12 mm = 0.012 m

frequency = 7 Hz

v = 0.012 * 7 = 0.084 m/s

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3 years ago

if a man travels 10m north in 4s, stops for 20s, then travels 20 meters east in 15s, what is the man's average velocity for the

arsen [322]

Answer:

The average velocity from 1 to 3 seconds is 20 m/s l. X/T = 0 m/1s = zero.

Explanation:

I hope that helped!

7 0

3 years ago

It takes 200 J of work to compress quasi-statically 0.40 mol of an ideal gas to one-fourth its original volume. Calculate the te

mario62 [17]

Answer : The temperature of the gas is, 43.4 K

Explanation :

The expression used for work done will be,

$w=-nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 200 J

n = number of moles of gas = 0.40 mol

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas = X

$V_2$ = final volume of gas = $\frac{X}{4}$

Now put all the given values in the above formula, we get :

$200J=-0.40mol\times 8.314J/moleK\times T\times \ln (\frac{(\frac{X}{4})}{X})$

$T=43.4K$

Thus, the temperature of the gas is, 43.4 K

3 0

4 years ago

If a walkman uses a standard 1.5 v battery. How much resistance is in the circuit if it uses a current of 0.01 A?

Goryan [66]

Answer:

R = 150 ohms.

Explanation:

According to Ohm's law,

V = IR

V = voltage across the walkman = 1.5 V (we assume that the battery has no internal resistance)

I = current used by the walkman = 0.01 A

R = resistance of the circuit = ?

1.5 = 0.01 × R

R = (1.5/0.01)

R = 150 ohms

Hope this Helps!!!

4 0

3 years ago

A felt-covered beanbag is fired into a empty wooden crate that sits on a concrete floor and is open on one side. The beanba

Phantasy [73]

Answer:

31.42383 m/s

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

$\mu$ = Coefficient of kinetic friction = 0.48

s = Displacement = 0.935 m

$m_1$ = Mass of bean bag = 0.354 kg

$m_2$ = Mass of empty crate = 3.77 kg

$v_1$ = Speed of the bean bag

$v_2$ = Speed of the crate

Acceleration

$a=-\frac{f}{m}\\\Rightarrow a=-\frac{\mu mg}{m}\\\Rightarrow a=-\mu g$

$a=--9.81\times 0.48=4.7088\ m/s^2$

From equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.7088\times 0.935+0^2}\\\Rightarrow v=2.96739\ m/s$

In this system the momentum is conserved

$m_1v_1=(m_1+m_2)v_2\\\Rightarrow v_1=\frac{(m_1+m_2)v_2}{m_1}\\\Rightarrow u=\frac{(0.354+3.77)\times 2.69739}{0.354}\\\Rightarrow u=31.42383\ m/s$

The speed of the bean bag is 31.42383 m/s

8 0

4 years ago

C) Explain the following.Keftles, cooking pans and iron boxes have polished surfaces​

C) Explain the following.Keftles, cooking pans and iron boxes have polished surfaces