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OLEGan [10]
3 years ago
15

C) Explain the following.Keftles, cooking pans and iron boxes have polished surfaces​

Physics
1 answer:
Monica [59]3 years ago
5 0

Answer:

Polished surfaces reduce heat loss

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a 1.05 kg water bottle is sitting on the teacher's desk it is .20 m tall and has a radius of .03 m find the force that the water
arsen [322]
The force applied would be 1.05*9.8 = 10.3 N
the pressure is equal to F/a
area will be πr^2 = 0.002826
thus pressure will be = 10.3/0.002826= 3644.72 N/m^2
4 0
3 years ago
After fixing a flat tire on a bicycle you give the wheel a spin. Its initial angular speed was 5.40 rad/s and it rotated 12.3 re
zaharov [31]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of angular motion.

By definition, acceleration can be expressed as the change in angular velocity squared over a given period of distance traveled.

\alpha = \frac{\omega^2}{2\theta}

where,

\omega = Angular velocity

\theta = Angular displacement.

In turn, as a function of time, we can represent it as,

\alpha = \frac{\omega}{t}

For our case we have to,

\omega = 5.4rad/s

\theta = 12.3rev = 12.3rev(\frac{2\pi rad}{1rev})=24.6\pi rad

PART A) In the case of angular acceleration we have to,

\alpha = \frac{\omega^2}{2\theta}

\alpha = \frac{(5.4)^2}{2*24.6\pi}

\alpha = 0.1886rad/s^2

PART B) Through the definition of angular acceleration as a function of time we can calculate it,

\alpha = \frac{\omega}{t}

t = \frac{\omega}{\alpha}

t = \frac{5.4}{0.1886}

t = 28.63s

3 0
4 years ago
Which is an example of a wedge?<br> A.<br> B<br> C<br> D
Salsk061 [2.6K]

Answer:

B I believe, because the axe is wedged into the log

4 0
3 years ago
Read 2 more answers
A gardener uses a water hose to fill a 30.0 L bucket. The gardener notes that it takes 1.00 min to fill the bucket. A nozzle wit
GalinKa [24]

Answer:

The distance can the water be projected is 4.51 m

Explanation:

The speed of the water in the hose is equal to:

v1 = R/A1

If we solve the continuity for v2:

v2 = R/A2 (eq. 1)

The equation for the vertical position is:

yf = yi + vy*t - (1/2)gt²

yi = 0

vy = 0

Clearing t:

t=\sqrt{\frac{-2y_{f} }{g} } (eq. 2)

The equation for position is:

xf = xi + vxt = 0 + v2t = v2t (eq. 3)

Replacing equation 1 and 2 in equation 3:

x_{f} =\frac{R}{A_{2}  } \sqrt{\frac{-2y_{f} }{g} } =\frac{30}{0.5} \sqrt{\frac{(-2)*(-1)}{9.8} }*\frac{1000}{60}  =451.75cm=4.51m

6 0
3 years ago
Put the celestial bodies in order from earliest to latest.
gavmur [86]
The answer is : <span>Planetesimals, protoplanets, planets.  This is the order of the celestial body from earliest to latest.  </span><span>A </span>protoplanet<span> is a massive object that will eventually become a planet. </span><span>They are at first formed by the accumulation of </span>planetesimals<span> into </span>protoplanets<span>, then into planets.</span>
4 0
3 years ago
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