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OLEGan [10]
3 years ago
15

C) Explain the following.Keftles, cooking pans and iron boxes have polished surfaces​

Physics
1 answer:
Monica [59]3 years ago
5 0

Answer:

Polished surfaces reduce heat loss

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An electron (mass 9 × 10-31 kg) is traveling at a speed of 0.92 in an electron accelerator. An electric force of 1.4 × 10-13 N i
pogonyaev

Given Information:

Mass of electron = m = 9x10⁻³¹ kg

initial speed of electron = v₁ = 0.92c

Force = F =  1.4x10⁻¹³ J

Distance = d = 3 m

Required Information:

Final speed of electron = v₂ = ?

Answer:

Final speed of electron = v₂ = 2.974x10⁸ m/s

Explanation:

As we know from the conservation of energy,

E₂ - E₁ = W

E₂ = E₁ + W

Where E₂ is the final energy of electron and E₁ is the initial energy of electron

The above equation can be written in the form of particle energy

γ₂mc² = γ₁mc² + W

where γ₁ and γ₂ are given by

γ₁ = 1/√1 - (v₁/c)²

γ₂ = 1/√1 - (v₂/c)²

First calculate γ₁

γ₁ = 1/√1 - (0.92c/c)²

γ₁ = 2.55 m

Now calculate γ₂

γ₂ = (γ₁mc² + W)/mc²

First we need to find the work done

W = F*d

W = 1.4x10⁻¹³*3

W = 4.2x10⁻¹³ J

so γ₂ is

γ₂ = (2.55*9x10⁻³¹*(3x10⁸)² + 4.2x10⁻¹³)/9x10⁻³¹*(3x10⁸)²

γ₂ = 7.73

Now we can find the new speed of the electron

γ₂ = 1/√1 - (v₂/c)²

Re-arranging the above equation results in

v₂ = c*√(1 - 1/γ₂²)

v₂ = 3x10⁸*√(1 - 1/7.73²)

v₂ = 2.974x10⁸ m/s

4 0
3 years ago
A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
Alex787 [66]

Answer:

47 ms

well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.

The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]

so t = sqrt(2*100/9.8) = 4.52s.

The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s

The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.

so the final velocity is = sqrt(44.3^2 + 14.4^2) = 47.ms

4 0
3 years ago
If a ball is dropped into a very viscous liquid it will
Dafna1 [17]
It will go to the bottom of the liquid very slowly. Good Luck!
7 0
3 years ago
What is the scientific method
Alex_Xolod [135]
The scientific method is an empirical tool that can be used to study phenomenon by asking questions, conducting experiments, and making observations to prove or disprove hypotheses. The scientific method has been used as a baseline tool in hard and social sciences to conduct experiments and to make conclusions about phenomenon in our natural world. 
7 0
3 years ago
Read 2 more answers
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.
BartSMP [9]

Answer:

The value of g in Kepler-12b is 3.85 m/s^{2}

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

W = m.g  (1)

Where m is the mass and g is the value of the gravity

F = G \frac{M.m}{R^{2}}  (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

m.g = G \frac{M.m}{R^{2}}  (3)

Then g will be isolated from equation 3:

g = G \frac{M.m}{m.R^{2}}

g = \frac{G.M}{R^{2}}  (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

d = 2R (5)

Where d and R are the diameter and radius of Jupiter

d_{jupiter} = 2(69911000 m)

d_{jupiter} = 139822000 m

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

d_{Kepler-12b} = 1.7(d_{jupiter})

d_{Kepler-12b} = 1.7(139822000 m)

d_{Kepler-12b} = 237697400 m

By means of equation 5 the radius of Kepler-12b can be known:

R_{Kepler-12b} = \frac{d}{2}

R_{Kepler-12b} = \frac{237697400 m}{2}

R_{Kepler-12b} = 118848700 m

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of 1.898x10^{27} kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

m_{Kepler-12b} = 0.43(m_{jupiter})

m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)

m_{Kepler-12b} = 8.161x10^{26} Kg

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}

g = 3.85 m/s^{2}

Hence, in Kepler-12b the gravity has a value of 3.85 m/s^{2}

8 0
3 years ago
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