Answer:
Chocolate melts and becomes really sticky once heated.
Add-on:
hope that helped at all.
Answer:
MM = 5,521.54 g/mol
Explanation:
To solve this, we need to use the expression for osmotic pressure which is the following:
π = MRT (1)
Where:
M: Concentration of the solution
R: gas constant (0.082 L atm/ mol K
T: temperature in K
25 °C in Kelvin is: 25 + 273.15 = 298.15 K
Now, we do not have the concentration of the solution, but we do have the mass. and the concentration can be expressed in terms of mass, molar mass and volume:
Concentration (M) is:
M = n/V (2)
and n (moles) is:
n = m/MM (3)
Therefore, if we replace (2) and (3) in (1) we have:
π = mRT/V*MM
Solving for MM we have:
MM = mRT/πV (4)
All we have to do now, is replace the given data and we should get the value of the molar mass:
MM = 6.143 * 0.082 * 298.15 / 0.1 * 0.272
MM = 150.1859 / 0.0272
<em>MM = 5,521.54 g/mol</em>
<em>This is the molar mass.</em>
To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas 2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol
Answer:
1).....for the specific heat capacity(c) of water is 4200kg/J°C..
....guven mass(m)=320g(0.32kg)
...change in temperature(ΔT) =35°C
from the formula
Q=mcΔT
Q=0.32Kg x 4200kg/J°C x 35°C
Q=47,040Joules
