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vodomira [7]
3 years ago
12

In what part of a volcano would you expect to find rocks with the coarsest grains

Physics
1 answer:
galben [10]3 years ago
4 0

Answer:

The correct answer is: in the magma chamber.

Explanation:

The volcanoes are creating igneous rocks, and they can be intrusive and extrusive. The intrusive ones are forming deep into the ground, while the extrusive are forming on the surface. Where the rocks are formed makes a big difference in their crystals size. The rocks that form by magma that has cooled the deepest into the ground would have the largest crystals, thus the coarsest grains. The reason for this is that the magma that has been cooling the deepest into the ground will be exposed to higher temperatures and pressures, which will lead to a very slow cooling off. Because the cooling off will be at such a slow rate, the crystals will have enough time to became much larger. The deepest part of a volcano is its magma chamber, thus it will be the place that will produce the coarsest grained igneous rocks.

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uysha [10]

Answer:

  n = 1 + R / f

Explanation:

The equation of the constructor is optical is

          1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and image, respectively

The exercise tells us that it is a concave lens with focal length fo, in these lenses the focal length is negative. The relationship to calculate the focal length is

         1 / f = (n -n₀) (1 /R₁ - 1 /R₂)

where is n₀ the refractive index of the medium that surrounds the lens in this case it is air with n₀ = 1, you do not indicate the type of lens, but the most used lens is the concave plane, in this case R₂ = ∞, so which 1 / R₂ = 0, let's substitute

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         n - 1 = R₁ / f

let's calculate

         n = 1- R₁ / f

remember that the radius of curvature is negative, so the equation is

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8 0
4 years ago
Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52
krek1111 [17]

Answer:

t = 1.31 s

Explanation:

Given that,

The top of a roof is located 8.52  meters above the ground.

We need to find the time required for the shingles to reach  the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

s=ut+\dfrac{1}{2}gt^2

Where

t is the time and u = 0

s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 8.52}{9.8}} \\\\t=1.31\ s

So, it will take 1.31 seconds for the shingles to reach the ground.

5 0
3 years ago
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