Answer:
n = 1 + R / f
Explanation:
The equation of the constructor is optical is
1 / f = 1 / p + 1 / q
where f is the focal length, p and q are the distance to the object and image, respectively
The exercise tells us that it is a concave lens with focal length fo, in these lenses the focal length is negative. The relationship to calculate the focal length is
1 / f = (n -n₀) (1 /R₁ - 1 /R₂)
where is n₀ the refractive index of the medium that surrounds the lens in this case it is air with n₀ = 1, you do not indicate the type of lens, but the most used lens is the concave plane, in this case R₂ = ∞, so which 1 / R₂ = 0, let's substitute
1 / f = (n-1) / R₁
n - 1 = R₁ / f
let's calculate
n = 1- R₁ / f
remember that the radius of curvature is negative, so the equation is
n = 1 + R / f
Answer:
t = 1.31 s
Explanation:
Given that,
The top of a roof is located 8.52 meters above the ground.
We need to find the time required for the shingles to reach the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

Where
t is the time and u = 0

So, it will take 1.31 seconds for the shingles to reach the ground.
If the climber is not accelerating then a=0. Then F=ma=0. This is because the upward force of the rope is equal and opposite to the force due to gravity. So the net (total) force is 0
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