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Gemiola [76]
3 years ago
5

Determine the value of the equilibrium constant (report

Chemistry
1 answer:
katovenus [111]3 years ago
6 0

Answer:

Kps = 6.56e⁻⁹

Explanation:

This is a solubility equilibrium

PbI₂  (s)  ⇄  Pb²⁺  +  2I⁻

Expression for Kc will be:

[I⁻]²  . [Pb²⁺] / [PbI₂]

But we do not have to consider the solid. It does not have a physical sense.  Amount of solid without dissolving, doesn't affect the ions concentrations.

We talk about Kps (Constant for solubility product)

Kps = [I⁻]²  . [Pb²⁺]

Kps = (0.00081)²  .  0.01 → 6.56x10⁻⁹

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
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We'll begin by calculating the number of mole of F₂ that reacted.

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Divide both side by 22.988

n = 18 / 22.988

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From the balanced equation above,

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Finally, we shall determine the mass of 1.566 moles of NaCl.

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Mass = mole × molar mass

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Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

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