Answer:
CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4
Answer:
λ = 1*10⁻¹⁰m
Explanation:
Frequency (f) = 3.0*10¹²MHz = 3.0*10¹⁸Hz
Speed (v) = 3.0*10⁸m/s
Speed (v) of a wave = frequency (f) * wavelength (λ)
V = fλ
Solve for λ,
λ = v / f
λ = 3.0*10⁸ / 3.0*10¹⁸
λ = 1*10⁻¹⁰m
λ = 0.
substitute: <span><span>t<span>1/2</span></span>=<span><span>ln(2)</span>k</span>→k=<span><span>ln(2)</span><span>t<span>1/2</span></span></span></span>
Into the appropriate equation: <span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−kt</span></span></span>
<span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−<span><span>ln(2)</span><span>t<span>1/2</span></span></span>t</span></span></span>
<span>[A<span>]t</span>=(250.0 g)∗<span>e<span>−<span><span>ln(2)</span><span>3.823 days</span></span>(7.22 days)</span></span>=67.52 g</span>
Answer:
propagation of disturbances—that is, deviations from a state of rest or equilibrium—from place to place in a regular and organized way. Most familiar are surface waves on water, but both sound and light travel as wavelike disturbances, and the motion of all subatomic particles exhibits wavelike properties.
Explanation:
