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Lunna [17]
3 years ago
15

students calculated the circumference of a globe to be 60.0 cm. The actual circumference of the glide is 63 cm. The percent devi

ation of the students calculation was. 1. 0.48% 2. 2.8% 3. 5.0% 4. 21%

Chemistry
2 answers:
Brrunno [24]3 years ago
7 0

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

To calculate the percentage error, we use the equation:

\%\text{ error}=\frac{|\text{Experimental value - Actual value}|}{\text{Actual value}}\times 100

We are given:

Experimental value of circumference = 60.0 cm

Actual value of circumference = 63 cm

Putting values in above equation, we get:

\%\text{ error}=\frac{|60.0-63|}{63}\times 100\\\\\%\text{ error}=4.8\%

Hence, the correct answer is Option 2.

Naily [24]3 years ago
6 0
#2. Percent error (or deviation) is calculated as ((TV-EV)/EV))*100
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A solution contains an unknown amount of dissolved magnesium. Addition of
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Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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