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3 years ago

Write a two column proof (or a flow proof. Whichever one works for you).

Mathematics

1 answer:

Norma-Jean [14]3 years ago

4 0

Plugging into the Given Formula the value of y:

$7(6) = 8x - 14$

Multiply the left side:

$42 = 8x - 14$

Add 14 to both sides to get:

$56 = 8x$

Divide both sides by 8 and we get:

$7 = x$

Therefore, x=7 and the proof is complete

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3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h

lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0

3 years ago

Read 2 more answers

What value of x satisfies

LenaWriter [7]

Answer:

See explanation

Step-by-step explanation:

The given trigonometric equation is $cos(90-x)=-\frac{\sqrt{3} }{3}$ .

We take the inverse cosine of both sides to get:

$90-x=cos^{-1}(-\frac{\sqrt{3} }{3})$

$90-x=125$

$x=125-90$

$x=-35\degree=325\degree$ to the nearest degree

None of the options satisfies the given equation.

But if the question is actually;

$cos(90-x)=-\frac{\sqrt{3} }{2}$

Then;

$90-x=\cos^{-1}(-\frac{\sqrt{3} }{2})$ .

$90-x=210$ .

$x=-120\degree$ .

$x=360-120=240\degree$ .

In this case the answer will be B

5 0

3 years ago

Read 2 more answers

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago

What is the y-intercept of the function f(x)=4 - 5x?<br> -5<br> -4<br> 4<br> 5

pantera1 [17]

Answer:

b = 4

Step-by-step explanation:

Use the slope-intercept form y = m x + b to find the y-intercept b .

8 0

3 years ago

Read 2 more answers

In the picture below, what is the approximate area that is shaded blue?

Iteru [2.4K]

I think it’s C sorry if I’m wrong

7 0

3 years ago