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d1i1m1o1n [39]
3 years ago
13

Pete the penguin loves to self down his favorite hill.If he hits a speed of 50m/s after 5 seconds,what is the acceleration

Mathematics
1 answer:
Vilka [71]3 years ago
8 0
I have to admit I don't know what exactly you are asking, but I think this is it: 10m/s.
Divide m/s by time.
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Prove: An odd number cubed is an odd number. (2n + 1)^3 = [ ? ]n^3 + [ ? ]n^2 + [ ? ]n [ ? ](4n3 + 6n2 + 3n) + [ ? ] = an odd​
anastassius [24]

Step-by-step explanation:

We know that odd * odd = odd

Thus odd*odd*odd = odd*odd = odd

6 0
3 years ago
(1,3), m = - 3/4 using that as a fraction write an equation in point-slope form
sukhopar [10]
Y=mx+b   m=-3/4  (1,3)
3=-3/4(1)+b
3=-3/4+b
b=3 3/4

y=-3/4+3 3 3/4
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3 years ago
VOLLEYBALL. MY VOLLEYBALL PLAYERS THIS QUESTION IS FOR YOU.
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Step-by-step explanation:

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5 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
3 years ago
Read 2 more answers
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