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QveST [7]
1 year ago
10

How would you distinguish benzoic acid and benzyl alcohol by their infrared spectra?

Chemistry
2 answers:
Wewaii [24]1 year ago
7 0

It is important to contrast and compare the OH peaks in the IR spectra of benzyl alcohol and benzoic acid.

<h3>What does benzoic acid's IR spectrum look like?</h3>
  • The fingerprint region is the region between wavenumbers 1500 and 400 cm-1 on the right side of the infrared spectrum of benzoic acid.
  • The benzoic acid molecule's atoms vibrate in a unique pattern that involves intricately overlapping vibrations, which causes it.

<h3>What does benzyl alcohol's IR spectrum look like?</h3>
  • A peak at 700 is typically used to indicate a C-Cl bond.
  • At 1500, there are a couple more peaks that are focused on a C=C bond.

<h3>How do IR spectra work?</h3>
  • The IR spectrum is made up of the radiation's wave number divided by its percent transmittance (or absorbance) through molecules.

To learn more about IR spectrum visit:

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#SPJ4

Vadim26 [7]1 year ago
3 0

The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.

<h3>What is the IR spectra of Benzoic acid?</h3>
  • The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region.
  • It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.
<h3>What is the IR spectra of Benzyl alcohol?</h3>
  • A C-Cl bond is frequently shown by a peak at 700.
  • There are a few more peaks at 1500 that are directed at a C=C bond.
<h3>What is IR spectra?</h3>

The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.

Learn more about IR spectra here:

brainly.com/question/22033021

#SPJ4

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The bonds found between water molecules are called:

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Explanation:

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Chlorine has two naturally occurring isotopes, 35C1 Gsotopic mass 34.9689 amu) and 370 (isotopic mass 36.9659 amu). If chlorine
Lilit [14]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 75.77% and 24.23% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 34.9689 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 36.9659 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

  • Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

35.4527=[(34.9689\times x)+(36.9659\times (1-x))]\\\\x=0.7577

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.7577\times 100=75.77\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.7577)=0.2423\times 100=24.23\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 75.77% and 24.23% respectively.

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