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Harlamova29_29 [7]
3 years ago
11

Iron pyrite, FeS2, is known as Fool's Gold because it is a shiny yellow solid which is similar in appearance to gold. Iron pyrit

e is an ionic compound. Gold is a metallic element.
- Iron pyrite, FeS2, contains positive and negative ions. The positive ion is Fe2+.

1) What is the formula of the negative ion?​
Chemistry
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

Explanation:

The algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

In order to know the formula of the negative Sulfur ion in pyrite, we must determine its oxidation state.

Let us make the make the oxidation number of sulfur = x

Therefore, FeS₂:

                      +2 +2x = 0

                      +2 = -2x

                       x = -1

The formula of the negative ion is S⁻

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A sample of limestone (calcium carbonate, CaCO3) is heated at 950 K until it is completely converted to calcium oxide (CaO) and
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Therefore, volume of CO₂ produced in the first step is 9141.404 L

Explanation:

Equations of reactions:

A: CaCO₃(s) ---> CaO(s) + CO₂(g)

B: CaO(l) + H₂O(l) ---> Ca(OH)₂(s)

Molar mass of CaCO₃ = 100 g; molar mass of CaO = 56 g; molar mass of CO₂ = 44 g molar mass of H₂P = 18 g; molar mass of Ca(OH)₂ = 74 g

From equation B, 1 mole of CaO produces 1 mole of Ca(OH)₂

This means that 56 g of CaO produces 74 g of Ca(OH)₂

mass of CaO that produces 8.47 kg or 8470 g of Ca(OH)₂ = 8470 g * 56/74 = 6409.73 g of CaO

Therefore, 6409.73 g of CaO were produced in reaction A

From reaction A, 1 mole of CaCO₃ produces 1 mole CaO and 1 mole of CO₂

Number of moles of CaO in 6409.73 g = 6409.73 g/56 g/mol = 114.46 moles

Therefore, 114.46 moles of CO₂ were produces as well.

Molar volume of gas at STP = 22.4 litres

Volume of CO₂ produced at STP = 114.46 * 22.4 L =2563.904 L

However, the above reaction took place at 950 K and 0.976 atm, therefore volume of CO₂ produced under these conditions are obtained using the general gas equation

Using P₁V₁/T₁ = P₂V₂/T₂

P₁ = 1.0 atm, V₁ = 2563.904 L, T₁ = 273 K, P₂ = 0.976 atm, T₂ = 950 K, V₂ = ?

V₂ = P₁V₁T₂/P₂T₁

V₂ = (1.0 * 2563.904 * 950)/(0.976 * 273)

V₂ = 9141.404 L

Therefore, volume of CO₂ produced in the first step is 9141.404 L

3 0
2 years ago
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