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3 years ago

C time

Chemistry

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

B. Spring balance - a device used for measuring the weight or force of gravity acting on an object.

Explanation:

A Force is any interaction that changes the motion or position of an obkpjectbthatbit is interacting with. Whenever there is an interaction between two objects, there is a force exerted by each of the objects on one themselves.

Forces are generally divided into contact forces and non-contact over field forces.

In contact forces, the two objects physically in contact with each other. Examples of contact forces are push or pull forces, frictional forces, tensional forces, spring forces, etc.

Non-contact forces are forces in which the two objects interacting do no need to be physically in contact with one another. Examples include, gravitational forces, magnetic forces, electrical forces, etc.

Instruments used in measuring forces are known as force gauges.

From the instruments listed above:

A. A ruler is an instrument used in measuring length

B. Spring balance is a device used for measuring the weight or force of gravity acting on an object.

C. A thermometer is an instrument used in measuring temperature

D. A windbvane is an instrument used in measuring wind direction.

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First: Calculate the number of moles of Kool-Aid powder needed to make 100mL of a 0.1M solution.

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For this question, we can use the molarity formula, which is as follows:

$Molarity= \frac{moles}{Liters}$

We know that we want a 0.1M solution in 100 mL, so we can plug those into the equation to find the number of moles required:

$0.1M= \frac{moles}{0.1L}$
$moles=0.01$

So now we know that the number of moles of the Kool-Aid powder is 0.01. We also know that the chemical formula for this powder is $C_{12} H_{22} O_{11}$ .

We can find the molar weight of this powder by taking the atomic weight from the periodic table and multiply it by the number of atoms in the compound. Let's find the molar weight of the powder:

Find the atomic weight of carbon:

$C=12.01 g$

There are 12 C's, so we multiply by 12:

$12.01g*12=144.12g$

Then we have 22 H's, each having an atomic weight of 1.008g:

$1.008g*22=22.18g$

And finally there are 11 O's, each with an atomic weight of 15.99g:

$15.99g*11=175.89g$

Then we add up all of the weights:

$144.12g+22.18g+175.89g=342.19g$ -> So we know that the molar weight of the Kool-Aid powder is 342.19g.

Now we can find the amount of grams that we need for the desired solution as follows:

$\frac{342.19g}{1mol}* \frac{0.01mol}{1}=3.42g$

So now we know that we need 0.01 moles of the powder, and we need 3.42g of the powder to make the desired solution.

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