Answer:
False
They dont conduct electricity that well/at all
Answer : (C) "Higher frequencies have larger spaces between lines".
Explanation:
In Young's experiment, the condition for constructive interference is given by :
.........(1)
n is order or number of lines observed
d is distance between slits
is the angle between the path and the line from screen to the slits.
We also know that, ![c=\nu \lambda](https://tex.z-dn.net/?f=c%3D%5Cnu%20%5Clambda)
or
![\lambda=\dfrac{c}{\nu}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bc%7D%7B%5Cnu%7D)
where,
c is the speed of light
is frequency
is wavelength
So, equation (1) turns into
![dsin\theta=n\dfrac{c}{\nu}](https://tex.z-dn.net/?f=dsin%5Ctheta%3Dn%5Cdfrac%7Bc%7D%7B%5Cnu%7D)
![\nu=\dfrac{n\ c}{d\ sin\theta}](https://tex.z-dn.net/?f=%5Cnu%3D%5Cdfrac%7Bn%5C%20c%7D%7Bd%5C%20sin%5Ctheta%7D)
So,
![\nu\propto n](https://tex.z-dn.net/?f=%5Cnu%5Cpropto%20n)
or
Higher frequencies have larger spaces between line.
So, correct option is (C).
Orbitals am only hold two electrons each, so 3 orbitals can hold 6 electrons
Answer:
Q = 4.056 J
Explanation:
∴ m = 406.0 mg = 0.406 g
∴ <em>C </em>= 1.85 J/g.K
∴ T1 = 33.5°C ≅ 306.5 K
∴ T2 = 38.9°C = 311.9 K
⇒ ΔT = 311.9 - 306.5 = 5.4 K
⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)
⇒ Q = 4.056 J