Polonium -210 decays once before it becomes a stable atom. What is that stable atom?

What is the percent composition by mass of hydrogen in nh4hco3

Simora [160]

Answer: The percent composition by mass of hydrogen in given compound is 6.33 %

Explanation:

We are given:

A chemical compound having chemical formula of $NH_4HCO_3$

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

$\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100$

Mass of compound = $[(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol$

Mass of hydrogen = $(5\times 1)=5g/mol$

Putting values in above equation, we get:

$\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%$

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0

3 years ago

A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c

gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58 kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change. Working with this equation, and assuming no heat is lost to the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= 135,583 J = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

Now that we have the heat of combustion, we need to calculate the molar heat.

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write the conversion factor as 135.58 kJ/ 4.40 g.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58 kJ/mol.

3 0

4 years ago

Explain reaction of metals with the following with the help of chemical equations; i) with acids ii) with oxygen iii) with water

Cerrena [4.2K]

i. When an acid reacts with metal, a salt and hydrogen are produced:

ii. When oxygen and metal react, metal oxide forms also known as rust

iii. Acid and water produce hydroxide ions

3 0

3 years ago

there are two processes involved in photosynthesis- the light reactions and the dark reactions- what is the end result of the li

GarryVolchara [31]

In light reactions there is successful photosynthesis due to the fact one of the primary reactants for photosynthesis in the first place. At the end of the light reaction, there will be the normal photosynthesis products formed which are glucose and oxygen. For the dark reaction no products will be formed

4 0

3 years ago

Which question can be answered using the scientific process?APEX

Xelga [282]

C sounds like the right answer in this question

5 0

3 years ago

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