Answer:
8. 171074.8 mL
9. 3475 mL.
Explanation:
8. Determination of the volume of the diluted solution.
Initial Molarity (M₁) = 14 M
Initial volume (V₁) = 523 mL
Final Molarity (M₂) = 0.0428 M
Final volume (V₂) =?
Using the dilution formula, we can obtain the volume of the diluted solution as follow:
M₁V₁ = M₂V₂
14 × 523 = 0.0428 × V₂
7322 = 0.0428 × V₂
Divide both side by 0.0428
V₂ = 7322 / 0.0428
V₂ = 171074.8 mL
Therefore, the volume of the diluted solution is 171074.8 mL
9. Determination of the volume of water added.
We'll begin by calculating the final volume of the solution. This can be obtained as follow:
Initial Molarity (M₁) = 3.2 M
Initial volume (V₁) = 973 mL
Final Molarity (M₂) = 0.7 M
Final volume (V₂) =?
M₁V₁ = M₂V₂
3.2 × 973 = 0.7 × V₂
3113.6 = 0.7 × V₂
Divide both side by 0.7
V₂ = 3113.6 / 0.7
V₂ = 4448 mL
Thus, the final volume of the solution is 4448 mL
Finally, we shall determine the volume of water added. This can be obtained as follow:
Initial volume (V₁) = 973 mL
Final volume (V₂) = 4448 mL
Volume of water added =?
Volume of water added = V₂ – V₁
Volume of water added = 4448 – 973
Volume of water added = 3475 mL
