No..since research can take different format
The pH of a buffer solution : 4.3
<h3>Further explanation</h3>
Given
0.2 mole HCNO
0.8 mole NaCNO
1 L solution
Required
pH buffer
Solution
Acid buffer solutions consist of weak acids HCNO and their salts NaCNO.
![\tt \displaystyle [H^+]=Ka\times\frac{mole\:weak\:acid}{mole\:salt\times valence}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdisplaystyle%20%5BH%5E%2B%5D%3DKa%5Ctimes%5Cfrac%7Bmole%5C%3Aweak%5C%3Aacid%7D%7Bmole%5C%3Asalt%5Ctimes%20valence%7D)
valence according to the amount of salt anion
Input the value :
![\tt \displaystyle [H^+]=2.10^{-4}\times\frac{0.2}{0.8\times 1}\\\\(H^+]=5\times 10^{-5}\\\\pH=5-log~5\\\\pH=4.3](https://tex.z-dn.net/?f=%5Ctt%20%5Cdisplaystyle%20%5BH%5E%2B%5D%3D2.10%5E%7B-4%7D%5Ctimes%5Cfrac%7B0.2%7D%7B0.8%5Ctimes%201%7D%5C%5C%5C%5C%28H%5E%2B%5D%3D5%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5CpH%3D5-log~5%5C%5C%5C%5CpH%3D4.3)
Answer:
158g
Explanation:
To calculate the "weight" (mass) of ethyl alcohol, we have to use this formula:
- Density will have units of gmL when dealing with a liquid or units of gcm3 when dealing with a solid.
The mass has units of grams, g.
The volume will have units of mL or cm3
We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:
density×volume=massvolume×volume
Density×Volume = Mass
0.789gmL×200.0mL
Thus, ethyl alcohol weighs 158g.
Answer:
4.25% is the final concentration of phosphoric acid.
Explanation:
Initial concentration of phosphoric acid = 
Initial volume of phosphoric acid = 
Final concentration of phosphoric acid = 
Final volume of phosphoric acid = 
( 1L = 1000 mL)



4.25% is the final concentration of phosphoric acid.