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sergiy2304 [10]
3 years ago
15

Which statements about the products of glycolysis is true? (check all that apply)?

Chemistry
1 answer:
Julli [10]3 years ago
3 0
These statements about the products of glycolysis are true:
1. ATP and NADH are the only high energy molecules produced by glycolysis.
2. A cell may either reduced or oxidized pyruvate depending on the cellular conditions.
Glycolysis is the process by which glucose molecules are broken down in the cell in the presence of oxygen in order to obtain energy. The products of glycolysis are 2 ATP, 2 NADH and 2 pyruvate molecules. The pyruvate formed can either by oxidized or reduced in the cell depending on whether oxygen is present or absent.<span />
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13. How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe(s) + I'(aq) 12(s) + Fe3+(aq)
Nat2105 [25]

Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)

Half reactions of oxidation and reduction are :

Oxidation : Fe(s)\rightarrow Fe^{3+}+3e^-        ......(1)

Reduction : 2I^-(aq)+2e^-\rightarrow I_2         .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : 2Fe(s)\rightarrow 2Fe^{3+}+6e^-        ......(1)

Reduction : 6I^-(aq)+6e^-\rightarrow 3I_2         .......(2)

The overall balanced chemical reaction will be:

2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

5 0
2 years ago
Determine the pH of a 5x10^-4 M solution of Ca(OH)2
miss Akunina [59]
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!</span>
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Answer:

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3 years ago
Determine the empirical formula for a compound that contains 15.8% carbon and 84.2% sulfer
nydimaria [60]

Answer:

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Explanation:

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2 years ago
State the importance of oxygen for germination process
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Plants need oxygen to survive. 
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