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____ [38]
3 years ago
12

What is 4.7 rounded to the nearest tenth

Chemistry
2 answers:
Margaret [11]3 years ago
8 0
5.0................ ..
irga5000 [103]3 years ago
7 0

Answer:

The answer is still 4.7

Explanation:

The first digit before a decimal (to the left) is called unit or one. However, the first digit after a decimal (to the right) is called tenth, and the one after that is called hundredth.

when rounding up, any digit greater than 4 will be rounded up to 1 and then added to the preceding number. But when the digit is less than 5, the number is rounded off to 0.

Hence, 4.7 is the same as 4.70 with the "7" being the tenth value and the "0" being the hundredth value. Hence, when 4.7 is rounded to the nearest tenth, it remains as 4.7 because its hundredth value is rounded off to "0" since it is less than "5".

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Find the mass of 3.66 moles of nitrogen.
Alex_Xolod [135]

Answer:

<h2>102.5166</h2>

Explanation:

Molar mass of N2 = 28.01

3.66 moles x 28.01 grams/mole = 102.5166

8 0
3 years ago
Read 2 more answers
Dumbledore decides to gives a surprise demonstration. He starts with a hydrate of Na2CO3 which has a mass of 4.31 g before heati
vovikov84 [41]

Answer:

Na₂CO₃.2H₂O

Explanation:

For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

The unknown is the value of x which is the amount of water of crystallisation.

Given values:

Starting mass of hydrate i.e Na₂CO₃.xH₂O = 4.31g

Mass after heating (Na₂CO₃) = 3.22g

Mass of the water of crystallisation = (4.31-3.22)g = 1.09g

To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

Simplest

Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

7 0
3 years ago
If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?
vovikov84 [41]

The reaction between hydrogen and oxygen to form water is given as:

H_2 + O_2 \rightarrow H_2O

The balanced reaction is:

2H_2 + O_2 \rightarrow 2H_2O

According to the balanced reaction,

4 g of hydrogen (4\times 1) reacts with 32 g of oxygen (2\times 16).

So, oxygen reacted with 29.4 g of hydrogen is:

\frac{29.4\times 32}{4} = 235.2 g

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

7 0
3 years ago
Enzymes in the small intestine break down proteins, carbohydrates, and lipids. These enzymes are named after the substrate they
svetoff [14.1K]

The enzymes and their respective substrates are as follows:

  • Protease enzymes such as trypsin and chymotrypsin break down proteins
  • Carbohydrate enzymes such amylase and maltase break down carbohydrates
  • Lipase enzyme breaks down lipids.

In the small intestine, a protease enzyme known as chymotrypsin breaks down protein, pancreatic amylase breaks down carbohydrates, while pancreatic lipase breaks down lipids.

More on biological enzymes can be found here: brainly.com/question/12194042

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How do you prepare copper sulphate​
Elena-2011 [213]
Prepare a 1% copper sulfate solution. To make this solution, weigh 1 gram of copper sulfate (CuSO4 ·5H2O), dissolve in a small amount of distilled water in a 100 ml volumetric flask and bring to volume. Label this as 1% copper sulfate solution.
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3 years ago
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