Temp must be Kelvin
38 C =
<span>
<span>
<span>
311.15
</span>
</span>
</span>
K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span>
<span>
<span>
7.1182746306
</span>
</span>
</span>
Liters
The formula to use is:
Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)
That happens because in oil and vinegar have a certain density weight.
-A<span>n object will float if it is less dense than the liquid it is placed in.
<span>-An object will sink if it is more dense than the liquid it is placed in.</span></span>
Answer:
2.3 L
Explanation:
when you have this eqaution you use P1V1T2=P2V2T1.
since you are looking for volume of gas cylinder that means you are looking for V2.
so you have your given P= 1.0 atm, V=2.5L, T=298K.
They ask you to use STP or standard pressure and temperature.
STP P= 1atm, STP T=273 K
so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2
so you now substitue so its now 1*273*2.5/ 1* 298= V
682.5/ 298= V
Lastly V= 2.2902 and you round to tenths so now you have
V= 2.3 L
Answer:
1.21 g of Tris
Explanation:
Our solution if made of a solute named Tris
Molecular weight of Tris is 121 g/mol
[Tris] = 100 mM
This is the concentration of solution:
(100 mmoles of Tris in 1 mL of solution) . 1000
Notice that mM = M . 1000 We convert from mM to M
100 mM . 1 M / 1000 mM = 0.1 M
M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris
0.1 M = mmoles of Tris / 100 mL
mmoles of Tris = 100 mL . 0.1 M → 10 mmoles
We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol
And now we determine the mass of solute, by molecular weight
0.010 mol . 121 g /mol = 1.21 g
