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Tju [1.3M]
3 years ago
12

*

Chemistry
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

A book held high over a desk

Explanation:

Gravitational potential energy, or GPE, is like height energy. The higher up an object is placed, the more GPE it has. Gravitational potential energy is the potential of a certain mass relative to another due to gravity. In this case you have a book held high over a desk and therefore since it's higher up it's going to have more potential energy due to gravity, which is why it has gravitational potential energy. Therefore your answer is "a book held high over a desk".

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In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i
fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0
3 years ago
The measure of how much salt will dissolve into 100 g of water is______
katen-ka-za [31]
Its solubility because you are looking at how much will desolve
5 0
4 years ago
During chemistry lab, Mrs. Black’s students placed an antacid tablet in a zip lock bag. They recorded the mass of the tablet in
Brilliant_brown [7]
It;s a physical change because the tablet dissolved and it made the water cooler
6 0
4 years ago
Read 2 more answers
Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2
Usimov [2.4K]

Answer:

\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:                      98.08           392.18

             2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

  • Use the molar mass of H₂SO₄ to convert  the mass of H₂SO₄ to moles of H₂SO₄
  • Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
  • Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}

(ii) Moles of H₂SO₄

\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ \text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}

(iv) Mass of Cr₂(SO₄)₃ \text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}

7 0
4 years ago
An example of a chemical change is burning a wood log to give a pile of ashes.<br> O True O False
serious [3.7K]

Answer:

True

Explanation:

<em>An example of a chemical change is burning a wood log to give a pile of ashes.</em> TRUE. In a chemical change there is a change in the identity of the substances, that is, some substances react (reactants) in order to form other substances (products).

A wood log is made of cellulose and organic compound that react with oxygen to produce carbon dioxide and water mainly.

5 0
3 years ago
Read 2 more answers
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