If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
1 answer:
Answer:
Explanation:
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In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:
Thus, by solving for the volume of the base as NaOH, we obtain:
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Answer:
has boiling point of 238 K
Explanation:
Boiling point depends on different intermolecular force such as molecular wight, dipole-dipole attraction force, hydrogen bonding, ionic attraction force.
Homonuclear diatomic molecules are covalent non-polar molecules and thereby free from dipole-dipole attraction force, hydrogen bonding and ionic interaction forces.
Hence, boiling point of homonuclear diatomic molecules depends solely on molecular weight.
We know, higher the molecular weight of a molecule, higher will be its boiling point. This phenomenon can be realized in terms of increasing london dispersion force with increase in molecular weight.
Decreasing order of molecular weight of halogen molecules :
>
>
>
So, decresing order of boiling point of halogen molecules:
>
>
>
Hence has boiling point of 238 K
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.
a) We need to find the major species from A to F.
Major Species at A:
1.
Major Species at B:
1.
2.
Major Species at C:
1.
Major Species at D:
1.
2.
Major Species at E:
1.
Major Species at F:
1.
b) pH calculation:
At Halfway point B:
pH = pK + log[
]/[H
]
pH = pK = 6.35
Similarly, at halfway point D.
At point D,
pH = pK + log [H
]/[H2
]
pH = pK = 10.33