Answer:
La cantidad de Ca3 (P04) 2 equivalente a 15, 4 moles es de 4774 gramos.
Explanation:
We need the weights of the elementos Ca, P and O, for calculate the weight of 1 mol:
Weight Ca=40 g
Weight P=31 g
Weight 0 = 16 g
Weight Ca3(PO4)2 = 3 x 40 g + 2 x (31 g + 4 x 16 g)
Weight Ca3(PO4)2 =310 g
1 molCa3(PO4)2---- 310 g
15, 4 mol Ca3(PO4)2-----x=(15, 4 molx 310 g)/1 mol = 4774 g
The total number of valence electrons is 20.(1 from hydrogen, 5 from nitrogen, and 7 from each fluorine so 14 for both) connect all the atoms with a single bond( each bond counts as 2) so far there is 6 electrons so you need to fill in the rest of the 14 and you get the result in the picture.
It is crucial to match your units of Pressure, Volume, number of mole, and Temperature with the units of R. If you use the first value of R, which is 0.082057 L atm mol-1K-1, your unit for pressure must be atm, for volume must be liter, for temperature must be Kelvin.
Answer:
Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they're ... Group A is given the special juice to drink while they work. Group ... 1. Control Group. Group B. 2. Independent Variable. volume of special juice.
Explanation:
