(2) Mg, Ca, and Ba have the most similar chemical properties, and we know this because of their coexistence in the group alkali earth metals (group 2) on the periodic table.

8 0

2 years ago

If 185 g of KBr are dissolved in 1.2 kg of water, what would be the expected change in boiling point? The boiling point constant

Fudgin [204]

Answer:

ΔTb = 0.66 C

Explanation:

Given

Mass of KBr = 185 g

Mass of water = 1.2 kg

Kb = 0.51 C/m

Explanation:

The change in boiling point (ΔTb) is given by the product of molality (m) of the solution and the boiling point constant (Kb)

$\Delta T_{b}= K_{b}* m$

$Molality = \frac{moles\ KBr}{Kg\ water} \\\\moles KBr = \frac{mass\ KBr}{Mol.wt\ KBr} = \frac{185}{119} = 1.555\\\\Molality (m) = \frac{1.555 }{1.2} =1.296 m\\$

[tex]\Delta T_{b}= 0.51 C/m * 1.296 m = 0.66 C[\tex]

6 0

3 years ago

Read 2 more answers

53. Why do real gases deviate from the ideal gas laws at low temperatures?

kirill115 [55]

Answer:

The volume occupied by molecules becomes a significant part of the total volume.

Attractions between molecules cause a reduction in volume.

Explanation:

C is wrong. The masses of molecules are constant.

8 0

2 years ago