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AURORKA [14]
2 years ago
8

An object with a mass of 3.2kg has a force of 16.3 newtons to the right and 6.7 newtons to the left applied to it. What is the r

esulting acceleration of the object?​
Chemistry
1 answer:
Pepsi [2]2 years ago
7 0

Answer:

3m/s²

Explanation:

Given parameters:

Mass of object  = 3.2kg

Force to the right = 16.3N

Force to the left  = 6.7N

Unknown:

Acceleration of the object  = ?

Solution:

To solve this problem, we use newtons second law of motion;

   Net force  = mass x acceleration

 Net force on object  = Force to the right  - Force to the left

 Net force  = 16.3N  - 6.7N  = 9.6N

    So;

         9.6  = 3.2 x a

              a = \frac{9.6}{3.2}   = 3m/s²

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Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

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  • On addition of reactant from equilibrium reaction ,shifts the equilibrium in forward direction.
  • On removal of product from equilibrium reaction, shifts the equilibrium in forward direction.
  • On addition of product from equilibrium reaction, shifts the equilibrium in backward direction.

UO_2(s) + 4 HF(g)\rightleftharpoons UF_4(g) + 2 H_2O(g)

1. Water vapor is removed

On removal of water vapor from equilibrium will decrease the product which will lead to moving forward of an equilibrium that is equilibrium will shift to right direction.

2. UF_4(g) is added

On addition of UF_4(g) from equilibrium will increase the reactant which will lead to moving forward of an equilibrium that is equilibrium will shift to right direction.

3.The reaction is done in a glass reaction vessel. HF(g) attacks and reacts with the glass

Due to reaction of HF with glass will result in decrease in amount of HF present at equilibrium. So, order to counter this equilibrium will shift in backward direction or in left direction.

4. If the reaction is endothermic, and you want to make the equilibrium shift to the right to maximize the products, would you heat or cool the reaction vessel.

I endothermic reaction , heat is added to the reaction for which we can treat heat as a reactant.Now, we want to shift the equilibrium to right which means in the forward direction.

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Answer:

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Explanation:

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Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)
creativ13 [48]

The question is incomplete, here is the complete question:

A solution contains 0.115 mol  H_2O and an unknown number of moles of sodium chloride. The vapor pressure of the solution at  30°C  is 25.7 torr. The vapor pressure of pure water at this temperature is 31.8 torr. Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)

<u>Answer:</u> The mass of sodium chloride in the solution is 0.714 grams

<u>Explanation:</u>

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,  

p^o = vapor pressure of solvent (water) = 31.8 torr

p^s = vapor pressure of the solution = 25.7 torr

i = Van't Hoff factor = 2

\chi_{\text{solute}} = mole fraction of solute (sodium chloride) = ?

Putting values in above equation, we get:

\frac{31.8-25.7}{31.8}=2\times \chi_{NaCl}\\\\\chi_{NaCl}=0.0959

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{NaCl}}=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+n_{\text{water}}}

We are given:

Moles of water = 0.115 moles

0.0959=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+0.115}\\\\n_{\text{NaCl}}=0.0122mol

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of NaCl = 0.0122 moles

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.0122mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}(0.0122mol\times 58.5g/mol)=0.714g

Hence, the mass of sodium chloride in the solution is 0.714 grams

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