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STatiana [176]
3 years ago
5

Resistance independent to : a. Shape b. Size c. Physical state d. None

Physics
2 answers:
lesantik [10]3 years ago
7 0

Answer:

d.none

Explanation:

because shape size and physical actually do are dependant

yan [13]3 years ago
7 0

Answer:

d

Explanation:

Resistance is given by

R = pL/A

Where A is length of wire , A is Area and p is resistivity of the material

From the expression above,

Resistance is affected by length and Area which means in consonance it's affected by the shape because shape affects the length and surface Area and Offcourse the size; the larger the surface area the Lower the resistance and the smaller the length and conversely the smaller the surface area and longer the length.

The physical state refers to the temperature of the substance. The higher the temperature the more electrons are free to move around and the lower the resistance.

Hence none of the option to a-c apply.

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Given data in the problem :-

  • Acceleration (a) = 4.0 m/s^2
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From Newton's Laws of Motion we know that ,

v = u + at  [t = Time taken by aircraft to cover the distance]

⇒ 34 = 0 + 4t

⇒ t = 34/4 s

∴  t = 8.5 s

From Newton's Laws of Motion we also know that ,

S = u.t + 1/2a.t^2

⇒ S = 0×8.5 + 1/2 × 4 × (8.5)^2 m

∴  S = 144.50 m

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2 years ago
An electric motor is traversed by 3.10²º electrons in 6 seconds. Determine the intensity of the current passing through the moto
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I = Q/Δt

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Q = 1.6×10⁻¹⁹(3×10²⁰) = 48C

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Explanation:

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A Galilean telescope adjusted for a relaxed eye is 36.2 cm long. If the objective lens has a focal length of 39.5 cm , what is t
GuDViN [60]

Answer:

The magnification is  m =  12

Explanation:

From the question  we are told that

   The object distance is u  = 36.2 \ cm

     The focal length is  v  =  39.5 \ cm

From the lens equation we have that

         \frac{1}{f}  =  \frac{1}{u} +  \frac{1}{v}

=>     \frac{1}{v}  =  \frac{1}{f}  - \frac{1}{u}

substituting values

       \frac{1}{v}  =  \frac{1}{39.5}  - \frac{1}{36.2}

       \frac{1}{v}  =  -0.0023

=>   v =  \frac{1}{0.0023}

=>   v =-433.3 \ cm

The magnification is mathematically represented as

         m =-   \frac{v}{u}

substituting values

        m =-   \frac{-433.3}{36.2}

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