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zzz [600]
3 years ago
12

Which statement is always true about objects which exert gravitational force on each other? A. They are a very large size. B. Th

ey exist only in outer space. C. They are a speed. D.They are a mass.​
Physics
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer:

The answer is D. They are a mass.

You might be interested in
Ice has a density of 0.920 g/cm3. An ice cubes mass is 100 g. What is its volume?
Tasya [4]

Answer:

\boxed {\tt 108.695652 \ cm^3}

Explanation:

Volume can be found by dividing the mass by the density.

v=\frac{m}{d}

The mass is 100 grams and density is 0.920 grams per cubic centimeters.

Therefore,

m=100 \ g \\d= 0.920 \ g/cm^3

Substitute the values into the formula.

v=\frac{100 \ g}{0.920 \ g/cm^3}

Divide. Note that the grams, or "g" will cancel each other out.

v- 108.695652 \ cm^3

The volume of the ice cube is 108.697652 cubic centimeters.

3 0
3 years ago
Chứng minh V=kq/r từ mối liên hệ giữ E và V
Marat540 [252]

Answer:V=Aq=KQr

Explanation:

Không biết V bạn kí hiệu ở đây là gì nhỉ? Có phải là điện thế?

Điện thế tại 1 điểm trong điện trường được định nghĩa là công làm vật dịch chuyển từ vị trí đó đến vô cùng. V = A/q

Chứng minh thì được, nhưng chỉ e bạn không có hiểu biết về nguyên hàm, tích phân nên không hiểu.

- Xét tại vị trí cách điện tích Q một đoạn x, khi đó điện tích q sẽ chịu 1 lực: dF=KQ.qx2

Điện tích q dịch chuyển 1 khoảng dx rất nhỏ. Khi đó công do lực điện trường gây ra là:

dA=dF.dx=KQ.qx2dx

Công để dịch chuyển điện tích q từ vị trí r đến vô cùng là:

A=∫∞rdA=∫∞rKQ.qx2dx=KQ.qr−KQ.q∞=KQ.qr

Theo đúng định nghĩa: V=Aq=KQr

4 0
3 years ago
A car is driving down the highway at a 50 m/s. Suddenly, the driver sees an accident and slams on his breaks, coming to a comple
vlada-n [284]

Given parameters:

Speed of the car = 50m/s

Time  = 10s

Unknown:

Distance traveled before the car stopped = ?

We need to establish speed - time - distance relationship.

Speed is the rate of change of distance with time. It is a scalar quantity .

Mathematically;

            Speed  = \frac{distance}{time}

    Distance  = speed x time

Input the parameters and solve;

    Distance  = 50 x 10  = 500m

The car traveled 500m before it stopped.

4 0
3 years ago
During what time interval was the object traveling most quickly?
anygoal [31]

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

v=\frac{7-3}{0-3}=-\frac{4}{3}m/s

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

v=\frac{5-3}{7-5}=\frac{2}{2}=1m/s

And the interval from 8s to 12s,

v=\frac{0-5}{12-8}=-\frac{5}{4}m/s

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

3 0
1 year ago
The figure shows the arrangement of master cylinder and slave cylinder of a part of braking system. The master cylinder piston,
Neko [114]

Answer:

a) 35 kPa

d) 140 N

c) 1) Increasing the brake fluid  pressure

2)  Increasing the slave piston surface area.

Explanation:

The parameters given are;

a) Force applied to the master cylinder piston = 28 N

Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²

The pressure P on the brake fluid is given by the formula for pressure as follows;

P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{28 \, N}{8 \times 10^{-4} \, m^2} = 35,000 \, N/m^2 = 35,000 \, Pa

The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa

b) Given that the area of the slave piston = 40 cm² = 0.004 m², we have from the formula for pressure, P;

P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{Applied \ force}{4 \times 10^{-3} \, m^2} = 35,000 \, N/m^2

Therefore;

Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N

c) The force, F produced by the slave cylinder piston is given by the relation;

F = Pressure × Area

Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;

1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston

2) Increasing the surface area of the slave piston.

4 0
3 years ago
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