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Leto [7]
3 years ago
5

Describe an environment in which the sound of a ringing cell phone could not be transmitted, and explain why the ringing wouldn'

t be heard. Assume that the phone is working and that the cell signal has not been interrupted
Physics
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

In a vacuum

Explanation:

Sound is a type of mechanical waves. Mechanical waves are waves that propagate through the oscillation of the particles in a medium, which can be either gas, liquid or solid.

A sound wave in air, for instance, is simply produced by the oscillations of the air particles back and forth along the direction of motion of the wave.

Given this definition, it is clear that mechanical waves (and so, sound waves as well) cannot be transmitted if there is no medium: therefore, they cannot be transmitted in a vacuum. So, the sound of the ringing bell would not be present in a vacuum.

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Match the sentences in Column A based on whether they describe radio waves, visible light waves, or both (Column B). Column A 1.
Andrew [12]
<span>1. They’re invisible - RADIO WAVES

2. They have colors. - VISIBLE LIGHT WAVES

3. They’re used to learn about dust and gas clouds. - BOTH

4. They can travel in a vacuum. </span> - BOTH<span>

5. They’re used to find the temperature of stars. </span>- VISIBLE LIGHT WAVES<span>

 6. They have energy. </span> - BOTH
8 0
3 years ago
Read 2 more answers
A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t
Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

(C) at 33.23 m the speed will be 12 m/s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height  is given by;

v = u - gt

u = gt

t = \frac{u}{g}

Time of flight, T = 2t

T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s

(C) the position of the ball at 12 m/s

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0
3 years ago
. (a) How long can you play tennis on the 800 kJ (about 200 kcal) of energy in a candy bar? (b) Does this seem like a long time?
galina1969 [7]

(a). The power of the candy bar is,

P=440\text{ W}

The time taken to play on 800 kJ energy of the candy bar is,

t=\frac{E}{P}

where E is the energy.

Substituting the known values,

\begin{gathered} t=\frac{800\times10^3}{440} \\ t=1.818\times10^3\text{ s} \\ t=1818\text{ seconds} \end{gathered}

As 1 minute is equal to 60 seconds,

Thus,

\begin{gathered} t=1818\text{ seconds} \\ t=\frac{1818}{60} \\ t=30.3\text{ min} \end{gathered}

Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.

(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.

The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.

8 0
1 year ago
A motion map for a motorcycle is shown. After how many seconds does the motorcycle have positive acceleration?
Ilya [14]
Answer: option D. 4

Reasoning:

Assuming that the time elapsed between any two consecutive dots is the same, and that the second dot marks second 1, the column with 3 dots marks second 2, and the dot right most marks second 3, the motorcycle has positive acceleration after 4 seconds.

That is because:

1) from the first dot to the second dot: the velocity the lenght of the arrow that models the velocity decrases, which means that the acceleration is negative.

2) In the nex group of dots the length of the arrow remains equal, which means that the velocity is constant and the acceleration is 0.

3) For the last dot, the length of the arrow is greater, which means that the velocity increases, and so the acceleration is positive.
7 0
4 years ago
20 POINTS MULTIPLE CHOICE
Shkiper50 [21]
If mass doubled and the force remained constant then the acceleration would also double

Hopes this helps
3 0
3 years ago
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