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Dmitrij [34]
4 years ago
9

Which statement is true about light when it slows down upon entering another medium? A. Light bends less, and there is greater r

efraction B. Light bends more, and there is greater refraction C. Light bends more, and there is less refraction D. Light bends less, and there is less refraction. HELP FAST PLEASE :( so stressed lol
Physics
2 answers:
Anvisha [2.4K]4 years ago
8 0
The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through.

So the answer would be: Light bends more, and there is greater refraction.
Fofino [41]4 years ago
5 0

Answer: B. Light bends more, and there is greater refraction.

Explanation:

Refraction is the bending of light when it moves from one medium into another. When light moves from a rarer medium to a denser medium from example from air to glass,  it travels slowly in glass and this leads to the bending of light towards the normal.

When light travels from a denser to a rarer medium for example from glass to air, the light travels faster and now bends away from the normal.

The normal is a line perpendicular to the boundary between the two substances.

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What happens to parallel light rays that strike a concave lens?
zhenek [66]
Due to the shape of the lens , parallel rays will be deviated
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3 years ago
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Ch 31 HW Exercise 31.10 7 of 15 Constants You want the current amplitude through a inductor with an inductance of 4.90 mH (part
sergey [27]

Answer:

f = 130 Khz

Explanation:

In a circuit driven by a sinusoidal voltage source, there exists a fixed relationship between the amplitudes of the current and the voltage through any circuit element, at any time.

For an inductor, this relationship can be expressed as follows:

VL = IL * XL (1) , which is a generalized form of Ohm's Law.

XL is called the inductive reactance, and is defined as follows:

XL = ω*L = 2*π*f*L, where f is the frequency of the sinusoidal source (in Hz) and  L is the value of the inductance, in H.

Replacing in (1), by the values given of VL, IL, and L, we can solve for f, as follows:

f = VL / 2*π*IL*L = 12 V / 2*π*(3.00*10⁻³) A* (4.9*10⁻³) H = 130 Khz

5 0
3 years ago
Common sports injury : ankle sprain , bone fracture , muscle strain , neck low back pain , shoulder pain. First aid needed
erastova [34]

Answer:

m

Explanation:

3 0
3 years ago
A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an
bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

\sum F_x = ma_x\\F_m - F_f = ma_x\\

Since the acceleration is zero, then;

F_m - F_f = 0\\Fm = F_f\\

Since;

F_m = mg sin \theta, \  hence \ F_f = mg sin \theta

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Natali5045456 [20]

Answer:

i = -12.7 cm; h =  5.07 cm

Explanation:

1. Find the focal length

The focal length of a concave spherical mirror is half of its radius of curvature.

f = ½r = ½ × 34.0 cm = 17.0 cm

2. Find the image distance

A convex mirror produces a virtual image behind the mirror, so the image distance is negative.

\begin{array}{rcl}\dfrac{1}{o} + \dfrac{1 }{i} & = & \dfrac{1}{f}\\\\\dfrac{1}{50.0} + \dfrac{1 }{i} & = & \dfrac{1}{-17.0}\\\\\dfrac{1}{i}  & = & \dfrac{1}{-17.0} - \dfrac{1}{50.0}\\\\& = & \dfrac{50.0 - (-17.0)}{500\times(-17.0)}\\\\& = & \dfrac{67.0}{-850}\\\\i & = & \dfrac{-850}{67.0}\\\\& = & \textbf{-12.7 cm}\\\end{array}

3. Find the image size

\begin{array}{rcl}\\\\\dfrac{h_{\text{i}}}{ h_{\text{o}}} & = & -\dfrac{i}{o} \\\\\dfrac{h_{\text{i}}}{ 20.0} & = & -\dfrac{-12.7}{50.0} \\\\h_{\text{i}} & = & 20.0 \times  \dfrac{12.7}{50.0}\\\\& = & \textbf{5.07 cm}\\\end{array}

5 0
3 years ago
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