Answer: the answer is 35.4
Explanation: the formula is mass x acceleration = tension - weight
weight is (3kg x 9.8 m/s)
acceleration is 2 m/s
mass = 3kg
The magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
The magnitude of the force on a charged particle moving in a magnetic field is given by the formula,
F= qvB
Here q is the charge on proton = 1.6 x 10^-19 C.
v is the velocity with which the particle is moving = 6.00 x 10^6 m/s
And B is the value of the magnetic field = 1.5 T
Putting the given values in the above equation,
F = 1.6 x 10^-19 x 6 x 10^6 x 1.5 = 1.44 x 10^-12 N.
Hence, the magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
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Answer:
n = 1.42
Explanation:
The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.
So, the refractive index of the medium is 1.42.
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