Answer:
Explanation:
The artificial gravity generated by the rotating space station is the same centripetal acceleration due to the rotational motion of the station, which is given by:
Here, r is the radius and v is the tangential speed, which is given by:
Here is the angular velocity, we replace (2) in (1):
Recall that .
Solving for :
Answer:
maybe make your own lock on the door:) that's what I did when I lived in a place with nosy roomates
Answer:
t₁ - t₂ = 0.0011 s
Explanation:
given,
y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
now,
y m = 6 mm ω = 600 rad/s
y₁ = + 2.0 mm y₂ = -2 .0 mm
now,
2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
so,
kx + (600 rad/s)t₁ + Φ = ......(1)
we have multiplied with π/180 to convert angle into radians
kx + (600 rad/s)t₂ + Φ = ......(2)
subtracting both the equation (1)-(2)
600(t₁-t₂) =
now,
t₁ - t₂ = 0.0011 s
time does any given point on the string take to move between displacements is equal to 0.0011 s
Answer:
inductance per unit length is
Explanation:
The diagram of coaxial cable is shown on the first uploaded image
From the question we are told that
The radius of the inner conductor is a
The current passing through the first cylindrical conductors is = I
The current passing through the first cylindrical conductors is = - I
The radius of the outer conductor is b
According to Ampere's law
∮
=>
=>
The magnetic flux on the coaxial cable can be mathematically represented as
Now the emf induced in the coaxial cable is mathematically represented as
=>
=>
=>
substituting for
dividing through by
B
Assume north and east as two sides of a right angled triangle. magnitude of the distance is then given by the length of the hypotenuse which is
where a = 1.2 km north
and b = 1.6 km east
magnitude = 2 km
Direction is given by the angle between them, that is atan(a/b) = 36.86 deg north of east = 53.1 deg east of north.