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Alexxx [7]
3 years ago
14

According to the exercise principle of balance, a workout should __________.

Physics
2 answers:
xxMikexx [17]3 years ago
6 0
<span>a. address all components of fitness 

</span>According to the exercise principle of balance, a workout should address all components of fitness.
<span>NOT:
</span>b. focus on balance and coordination 
<span>c. target specific areas for improvement </span>
<span>d. vary exercise activities over time</span>

8090 [49]3 years ago
6 0
<span>According to the exercise principle of balance, a workout should:


</span><span>a. address all components of fitness </span><span>

Explanation:


</span>The Balance Principle dictates that each one training should be properly proportioned so as to realize best results. This broad principle operates at several<span> levels of human performance.
All things </span>moderately apply to sports coaching moreover general health and well being
This principle suggests that the proper mixture of coaching activities, diet, and healthy way habits are needed for the best functioning
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A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block
gayaneshka [121]

The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

  • Mass of first block; m_1 = 5.0kg
  • Mass of second block, m_2 =10kg
  • Tension on first rope; T_1 =\ ?
  • Tension on second rope; T_2 =\ ?

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

Therefore, the tension in the second rope is 98 Newton

Learn More, brainly.com/question/18288215

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